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Coefficient of Friction [Needing Help!]

  1. Sep 28, 2009 #1
    1. The problem statement, all variables and given/known data
    If the kinetic coefficient of friction between ice skates and ice is 0.01, what is the average forward force necessary for a 500 Nt skater to maintain a constant forward velocity?

    2. Relevant equations
    f = (Uk)(N)

    3. The attempt at a solution

    f = (Uk) (N)
    f = (0.01) (500 Nt)
    f = 5 Nt

    Is this right? Just seems too simple. Can someone explain and walk me through this problem if I'm wrong.

    Also I realized from a diagram I did in my head Fapp - f = 0
    Fapp = f
    Fapp = (Uk) (N).....right???
  2. jcsd
  3. Sep 28, 2009 #2


    User Avatar
    Homework Helper

    Your calculation to get 5 N looks correct to me!
  4. Sep 29, 2009 #3
    Alright thanks a bunch.
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