Coefficient of kinetic friction between each block

[xstetsonx]

Two blocks are connected by a cord on a horizontal surface. A force F pulls on the 15-kg block as shown in the figure. Find the tension in the cord connecting the two blocks to each other if the coefficient of kinetic friction between each block and the ground is 0.2.
----------T=?-------
25KG box-------15kg box-------->F=150Nmy work:
(150N)-(0.2)((25kg)(9.8m/s^2)+(15kg)(9.8m/s^2))/(25kg+15kg)=acceleration(A)=1.79m/s^2

T-(0.2)(25kg)(9.8m/s^2)=(25kg)(1.79m/s^2)=T

correct me if i am wrong or tell me if i am right since no one has say anything yet

 

[Doc Al]

my work:
(150N)-(0.2)((25kg)(9.8m/s^2)+(15kg)(9.8m/s^2))/(25kg+15kg)=acceleration(A)=1.79m/s^2

Good.

T-(0.2)(25kg)(9.8m/s^2)=(25kg)(1.79m/s^2)[STRIKE]=T[/STRIKE]

Good. (Except for that last little bit.) Now just finish the job and solve for T.

 

[xstetsonx]

thanks my practice test doesn't have answer key so i just want to make sure