Coefficient of kinetic friction between each block

  • Thread starter xstetsonx
  • Start date
  • #1
78
0
Two blocks are connected by a cord on a horizontal surface. A force F pulls on the 15-kg block as shown in the figure. Find the tension in the cord connecting the two blocks to each other if the coefficient of kinetic friction between each block and the ground is 0.2.
----------T=?-------
25KG box-------15kg box-------->F=150N


my work:
(150N)-(0.2)((25kg)(9.8m/s^2)+(15kg)(9.8m/s^2))/(25kg+15kg)=acceleration(A)=1.79m/s^2

T-(0.2)(25kg)(9.8m/s^2)=(25kg)(1.79m/s^2)=T

correct me if i am wrong or tell me if i am right since no one has say anything yet
 
Last edited:

Answers and Replies

  • #2
Doc Al
Mentor
45,204
1,542


my work:
(150N)-(0.2)((25kg)(9.8m/s^2)+(15kg)(9.8m/s^2))/(25kg+15kg)=acceleration(A)=1.79m/s^2
Good.

T-(0.2)(25kg)(9.8m/s^2)=(25kg)(1.79m/s^2)[STRIKE]=T[/STRIKE]
Good. (Except for that last little bit.) Now just finish the job and solve for T.
 
  • #3
78
0


thanks my practice test doesn't have answer key so i just want to make sure
 

Related Threads on Coefficient of kinetic friction between each block

Replies
3
Views
1K
Replies
1
Views
6K
Replies
1
Views
2K
Replies
9
Views
3K
Replies
6
Views
7K
Replies
1
Views
17K
Replies
2
Views
2K
Replies
1
Views
2K
Replies
3
Views
4K
Replies
10
Views
9K
Top