I Coherence time for repeated spin measurements

  • Thread starter Thread starter aa2ll2
  • Start date Start date
Click For Summary
The discussion centers on the correlation function C(t,0) for repeated spin measurements on the same electron, which shows that for small time intervals, the results are identical (C(t,0)=1), while for larger intervals, the correlation approaches zero. The correlation function is defined in terms of the probabilities of obtaining the same or different measurement results. The dependence of C(t,0) on time is linked to the Hamiltonian of the system, particularly in the presence of noise, with the coherence time T_coh being a significant factor. The decay of off-diagonal terms in the density matrix is noted to follow an exponential decay model, suggesting a relationship between coherence time and the correlation function. Overall, the coherence time plays a crucial role in understanding the time dependence of the correlation in repeated spin measurements.
aa2ll2
Messages
6
Reaction score
1
TL;DR
"What is the half life of the correlation between repeated spin measurements on the same electron?
Consider repeated spin measurements, along the same axis, on the same electron, at t=0 and at t=t. For small t, the results are identical, so the correlation function, C(t,0)=1, but for large t, C(t,0) -> 0.

Define C(t,0) = P(same) - P(different) = N(same) - N(different) / N(same) + N(different), where N(same) is the number of trials where the measurements at t=0 and at t=t return the same result etc.

How does this correlation function depend on t?
 
Physics news on Phys.org
aa2ll2 said:
TL;DR Summary: "What is the half life of the correlation between repeated spin measurements on the same electron?

Consider repeated spin measurements, along the same axis, on the same electron, at t=0 and at t=t. For small t, the results are identical, so the correlation function, C(t,0)=1, but for large t, C(t,0) -> 0.

Define C(t,0) = P(same) - P(different) = N(same) - N(different) / N(same) + N(different), where N(same) is the number of trials where the measurements at t=0 and at t=t return the same result etc.

How does this correlation function depend on t?
It depends on the Hamiltonian for the system. For a free electron, the spin state does not evolve. The spin state would evolve in a magnetic field.
 
It's a noise question. So, the free particle spin evolving in noise, does not remain forever the same, with prob. 1, right? I actually have in mind an NV centre, which I think is free for the purpose to hand.
 
aa2ll2 said:
It's a noise question. So, the free particle spin evolving in noise, does not remain forever the same, with prob. 1, right? I actually have in mind an NV centre, which I think is free for the purpose to hand.
You'll need to specify a Hamiltonian for your "noise".
 
  • Like
Likes Lord Jestocost
The standard, coupling to bath, model. A bit of context may help. The single qubit coherence time is T_coh. I'm anticipating the time dependence should involve T_coh, something like C(t,0) = e^[-t/T_coh]. Or, are you saying coherence time is not pertinent?
 
aa2ll2 said:
The standard, coupling to bath, model. A bit of context may help. The single qubit coherence time is T_coh. I'm anticipating the time dependence should involve T_coh, something like C(t,0) = e^[-t/T_coh]. Or, are you saying coherence time is not pertinent?
Is this to do with quantum computing?
 
It is actually something that came up with loophole free Bell tests, but quite similar to computing.
 
Hi Perok,

Looking at some papers, the question of what hamiltonian to use seems a bit of a red herring. The starting point is the density matrix, where off diagonal terms decay as exp[-t/T_coh] In the model used for predicting the Bell violation in noise. My question should then be quite simple . How does the C(t,0) defined above depend on time?
 
aa2ll2 said:
Hi Perok,

Looking at some papers, the question of what hamiltonian to use seems a bit of a red herring. The starting point is the density matrix, where off diagonal terms decay as exp[-t/T_coh] In the model used for predicting the Bell violation in noise. My question should then be quite simple . How does the C(t,0) defined above depend on time?
There's not enough context in this thread for me to comment. Perhaps someone else who is more familiar with the specific subject matter may be able to help. But, in such specific cases, you ought to provide the full background to the question.
 
  • #10
Thanks for your attention to this matter.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K