Colliding Freight Cars: Kinetic Energy Transformed

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SUMMARY

The discussion centers on a physics problem involving two 5000-kg freight cars colliding on a level track, one moving at 1 m/s and the other at 2 m/s. The initial kinetic energies are calculated as 2500 J for the first car and 10,000 J for the second car. After the collision, the cars couple together, and the kinetic energy transformed into heat during the collision is determined by conserving momentum and calculating the kinetic energy post-collision. The correct answer for the kinetic energy lost to heat is 7500 J.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic principles of kinetic energy calculation
  • Knowledge of momentum conservation
  • Familiarity with energy transformation concepts
NEXT STEPS
  • Study the principles of momentum conservation in collisions
  • Learn how to calculate kinetic energy before and after collisions
  • Explore energy transformation in inelastic collisions
  • Investigate real-world applications of kinetic energy in transportation systems
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Students studying physics, educators teaching mechanics, and anyone interested in understanding energy transformations during collisions.

CanadianEh
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I am totally lost with this one... please explain if you know how to do it.


Two 5000-kg freight cars roll toward one another (one at 1 m/s and the other at 2 m/s) on a level track. Thus before they collide one car's kinetic energy is 2500 J and the other's is 10,000 J. They collide and couple together. The amount of kinetic energy turned into heat (mostly warming the couplers) in the collision is...

a. 2500 J.
b. 10,000 J.
c. 1250 J.
d. 7500 J.
e. 11,250 J.
 
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Try conserving momentum to figure out what the motion is after the collision. Then try to calculate the kinetic energy after collision and compare to the kinetic energy before the collision.
 

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