Collision of Two Protons: Separation at Momentary Stop

[ohheytai]

Two protons that are very far apart are hurled straight at each other, each with an initial kinetic energy of 0.15 MeV, where 1 mega electron volt is equal to 1x10^6 (1.6x10^-19) joules. What is the separation of the protons from each other when they momentarily come to a stop?

i got 4.58e-13 and it was wrong someone please help me i think i have no idea how to do this

 

[tiny-tim]

hi ohheytai!

(you meant 1.6 10^-19 J)

(try using the X² tag just above the Reply box )

show us your full calculations, and then we'll see what went wrong, and we'll know how to help

 

[ohheytai]

initial kinetic energy = 2 * 0.15 * 1106 (q) Joules.
q^2 / (4 pi eps0 dstop) = 2 * 0.15 * 1106 (q)
1 / (4 pi eps0 dstop) = 0.3 * 1106 / q
dstop = q / 0.3*1106*4*pi*eps0
yaaa as you can see I am losttt

 

[tiny-tim]

hi ohheytai!

(have a pi: π and an epsilon: ε )

i'm confused

what is 1106?

and can you please write it out more clearly?

 

[ohheytai]

1x10^6 sorry

 

[ohheytai]

i just redid it and got 4.58e-15 i think that's right is it?