Collision of Two Protons: Separation at Momentary Stop

AI Thread Summary
Two protons, each with an initial kinetic energy of 0.15 MeV, are analyzed for their separation when they momentarily stop. A participant initially calculated the separation as 4.58e-13 but found it to be incorrect. They were guided to show their full calculations for better assistance, leading to confusion over the constants used, particularly the notation for mega electron volts. After re-evaluating their calculations, the participant arrived at a new separation value of 4.58e-15, questioning its accuracy. The discussion highlights the complexities of calculating proton interactions and the importance of clarity in scientific notation.
ohheytai
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Two protons that are very far apart are hurled straight at each other, each with an initial kinetic energy of 0.15 MeV, where 1 mega electron volt is equal to 1x10^6 (1.6x10^-19) joules. What is the separation of the protons from each other when they momentarily come to a stop?

i got 4.58e-13 and it was wrong someone please help me i think i have no idea how to do this
 
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hi ohheytai! :smile:

(you meant 1.6 10-19 J)

(try using the X2 tag just above the Reply box :wink:)

show us your full calculations, and then we'll see what went wrong, and we'll know how to help :smile:
 


initial kinetic energy = 2 * 0.15 * 1106 (q) Joules.
q^2 / (4 pi eps0 dstop) = 2 * 0.15 * 1106 (q)
1 / (4 pi eps0 dstop) = 0.3 * 1106 / q
dstop = q / 0.3*1106*4*pi*eps0
yaaa as you can see I am losttt
 
hi ohheytai! :smile:

(have a pi: π and an epsilon: ε :wink:)

i'm confused :confused:

what is 1106?

and can you please write it out more clearly? :smile:
 


1x10^6 sorry
 


i just redid it and got 4.58e-15 i think that's right is it?
 
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