Collision problem: Two hockey pucks collide and stick together....

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SUMMARY

The discussion focuses on a two-dimensional collision problem involving two hockey pucks that collide at a 90-degree angle and stick together. The masses of the pucks are 0.71 kg and 0.52 kg, with initial velocities of 1.6 m/s and 3.8 m/s, respectively. The correct approach to solving the problem involves using momentum conservation principles, leading to a final speed of 2.52 m/s for the combined pucks after the collision. The discussion highlights the importance of treating the velocities as vector quantities rather than scalar speeds.

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Homework Statement


Two hockey pucks collide in a 90 degree angle and stick to each other. What's the speed of the hockey pucks after the collision and in what angle are the pucks moving in.

Homework Equations


m1=0.71kg
m2=0.52kg
v1=1.6m/s
v2=3.8m/s

The Attempt at a Solution


m1v1+m2v2=v(m1+m2)
=0.71kg*1.6m/s+0.52kg*3.8m/s=(0.71kg+0.52kg)*v
=v=(3.1kgm/s)/1.23kg=2.52m/s
 
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Hi Jeemeli and welcome to PF.

Is there something you wish to know about this? If so, please ask.
 
kuruman said:
Hi Jeemeli and welcome to PF.

Is there something you wish to know about this? If so, please ask.
My solution was wrong, Id like to know how to get the right answer
 
Jeemeli said:
m1v1+m2v2=v(m1+m2)
=0.71kg*1.6m/s+0.52kg*3.8m/s=(0.71kg+0.52kg)*v
You've gone from a correct formula involving vector velocities and applied it to scalar speeds.

If you walk 1.136 meters north and 1.976 meters east, how far from your starting position will you be as the crow flies?
 
Jeemeli said:
My solution was wrong, Id like to know how to get the right answer
In short, this is a two-dimensional collision.
 

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