Collisions Toolkit: Impulse, Momentum & Energy Formulas

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SUMMARY

This discussion focuses on essential formulas for analyzing collisions, specifically in the context of perfectly elastic and perfectly inelastic collisions. The key formulas include the impulse during elastic collisions, represented as Δp = 2μΔv, and for inelastic collisions, Δp = μΔv, where μ is the reduced mass calculated as μ = (m1m2)/(m1+m2). Additionally, post-collision momentum and energy are defined by the equations P_f = P_i ± Δp and E_f = (P_i ± Δp)²/(2m), respectively. The energy loss in perfectly inelastic collisions is quantified by ΔE = ½μΔv².

PREREQUISITES
  • Understanding of Newton's Third Law of Motion
  • Familiarity with the concept of reduced mass
  • Basic knowledge of momentum and energy conservation principles
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study the implications of Newton's Third Law in collision scenarios
  • Explore advanced topics in collision theory, such as impulse-momentum theorem
  • Investigate real-world applications of elastic and inelastic collisions in physics
  • Learn about energy conservation in multi-object collision systems
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Students studying physics, educators teaching collision mechanics, and anyone interested in understanding the mathematical principles behind collisions in mechanics.

neilparker62
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Just thought I'd post a couple of formulas which I have found useful when assisting (or should I say attempting to assist!) with collisions problems in the "Homework" forums. These formulas work on the basic premise that a collision is essentially a "Newton 3 event" in which equal and opposite impact forces act for a (usually) short period of time resulting in equal and opposite impulses on the colliding objects.

Collision impulse during perfectly elastic collisions:

$$ Δp = 2μΔv $$
where μ is the reduced mass of the colliding objects:
$$ μ=\frac{m_1m_2}{m_1+m_2} $$
and Δv is their relative velocity along the line of impact.

Collision impulse during perfectly inelastic collisions:

$$ Δp = μΔv $$

Post collision momentum and energy (applies to both colliding objects)

$$ P_f=P_i\pmΔp $$
$$ E_f=\frac{(P_i\pmΔp)^2}{2m} $$

Energy loss during perfectly inelastic collisions

$$ ΔE = ½μΔv^2 $$
 
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