Collisions Toolkit: Impulse, Momentum & Energy Formulas

Click For Summary
The discussion presents key formulas for analyzing collisions, emphasizing the principles of impulse, momentum, and energy. It explains that collisions can be viewed as events governed by Newton's third law, where equal and opposite forces create equal and opposite impulses. For perfectly elastic collisions, the impulse formula is Δp = 2μΔv, while for perfectly inelastic collisions, it is Δp = μΔv, with μ representing the reduced mass. The post-collision momentum and energy equations are also provided, illustrating how to calculate final momentum and energy based on initial values and impulse. These formulas are valuable for solving collision problems in physics.
neilparker62
Mentor
Science Advisor
Homework Helper
Education Advisor
Insights Author
Messages
1,200
Reaction score
702
Just thought I'd post a couple of formulas which I have found useful when assisting (or should I say attempting to assist!) with collisions problems in the "Homework" forums. These formulas work on the basic premise that a collision is essentially a "Newton 3 event" in which equal and opposite impact forces act for a (usually) short period of time resulting in equal and opposite impulses on the colliding objects.

Collision impulse during perfectly elastic collisions:

$$ Δp = 2μΔv $$
where μ is the reduced mass of the colliding objects:
$$ μ=\frac{m_1m_2}{m_1+m_2} $$
and Δv is their relative velocity along the line of impact.

Collision impulse during perfectly inelastic collisions:

$$ Δp = μΔv $$

Post collision momentum and energy (applies to both colliding objects)

$$ P_f=P_i\pmΔp $$
$$ E_f=\frac{(P_i\pmΔp)^2}{2m} $$

Energy loss during perfectly inelastic collisions

$$ ΔE = ½μΔv^2 $$
 
Last edited:
  • Like
Likes sophiecentaur
Physics news on Phys.org
For simple comparison, I think the same thought process can be followed as a block slides down a hill, - for block down hill, simple starting PE of mgh to final max KE 0.5mv^2 - comparing PE1 to max KE2 would result in finding the work friction did through the process. efficiency is just 100*KE2/PE1. If a mousetrap car travels along a flat surface, a starting PE of 0.5 k th^2 can be measured and maximum velocity of the car can also be measured. If energy efficiency is defined by...

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 19 ·
Replies
19
Views
6K
  • · Replies 11 ·
Replies
11
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
2K
  • · Replies 35 ·
2
Replies
35
Views
4K