Colombo's Law Gizmo - Force & Distance Equation

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Homework Help Overview

The discussion revolves around the relationship between force (F) and distance (d) for two charged objects, specifically exploring the equation derived from experimental results related to Coulomb's Law.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulation of an equation relating force to distance, with one participant suggesting a specific equation based on their findings. Others inquire about the graphical representation of the data and its implications for linearity and proportionality.

Discussion Status

The discussion is active, with participants sharing their findings and questioning the units associated with their results. Some guidance has been offered regarding the interpretation of the graph and the relationship between variables, but there is no explicit consensus on the final equation or its units.

Contextual Notes

Participants are navigating potential discrepancies in unit consistency and the implications of their experimental data on theoretical expectations. There is an emphasis on ensuring that the units of the derived constant align with established physical laws.

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Homework Statement


Write the equation that you determined from your results that shows the relationship between F and d for two charged objects.

Homework Equations

The Attempt at a Solution


I have determined a constant value that relates force to separation distance. The value is 8500 N/m^2
I'm assuming the equation is (8500 N/m^2)/r^2, where the 8500 N/m^2 is equal to the two charges and coloumb's constant multiplied together. and r is the distance between the two charges.
 
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Did you draw a F versus 1/d2 graph with your data?
 
First I drew F vs. 1/d graph which gave me a hyperbola and then my F vs. 1/d^2 graph gave me a linear line and i have calculated the slope of that linear line to be 8500 which has some percent error.
 
Yes, that shows that the relationship between F and 1/d2 is
linear or that there is a directly proportional relationship if the y-intercept
is close to zero Newton. The gradient is then the proportional constant,
which you determined as 8500. Have a careful look at its unit though.
The empirical equation (supply the units of your constant in the brackets)
is then
F = 8500 ( ) 1/d2 or r2
 
For it's units i get N/m^2 but when i actually multiply coulomb's constant and both q's together i get units of Nm^2 my slope should have the same units as the actual theoretical k.
 
The units of the independent variable is per meter square. So the units of the gradient will be N/m-2 which comes to Nm2
 

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