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Yazan975
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To determine the fourth term that, along with 12a^2bc, 8ab, and 4a^2cd, results in a least common multiple of 24a^3bc^2d, the necessary components are identified. The existing terms provide a least common multiple of 24a^2bcd, requiring an additional "a" and "c" in the fourth term. The coefficient of this new term must be an odd prime number that divides 24. The discussion highlights that the only odd prime factor of 24 is 3. Therefore, the fourth term should be 3a^1c^1, leading to the desired least common multiple.
Obviously, there is something elementary I am missing here.
To form the transpose of a matrix, one exchanges rows and columns, so the transpose of a scalar, considered as (or isomorphic to) a one-entry matrix, should stay the same, including if the scalar is a complex number. On the other hand, in the isomorphism between the complex plane and the real plane, a complex number a+bi corresponds to a matrix
in the real plane; taking the transpose we get
which then corresponds to a-bi...