MHB Common Multiple, what is the fourth term

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The discussion centers on finding the fourth term in a set of algebraic expressions to achieve a specific least common multiple (LCM). The given terms are 12a²bc, 8ab, and 4a²cd, with their LCM calculated as 24a²bcd. To reach the desired LCM of 24a³bc²d, an additional term must contribute one more 'a' and one more 'c'. The coefficient of this new term must be an odd prime number that divides 24, which is determined to be 3.

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Can you show what you've tried or your thoughts on how to begin?
 
Three of the terms are 12a^2bc, 8ab, and 4a^2cd. To find the least common multiple of those 3, note that 12= 2^2(3), 8= 2^3, and 4= 2^2. The least common multiple of those three is 2^3(3)= 24. The highest power of a is a^2 and the highest power of b, c, and d is 1 for all three. So the least common multiple of those three terms is 24a^2bcd. We want another term such that the least common multiple of all four terms is 24a^3bc^2d. We already have the "24", the "b" and "d", two of the three "a"s, and one of the two "c"s. It looks like we need just one more "a" and one more "c". Any coefficient must be already included in the "24". What is an odd prime number that divides 24?
 
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