Commutate relation of lowering operator and sperical tensor operators

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The discussion centers on the commutation relation between the lowering operator (J-) and spherical tensor operators, specifically the presence of a minus sign in the equation. Some sources include the minus sign, while others do not, leading to confusion about which is correct. The resolution lies in the conventions used for defining the spherical tensor operators, which can vary. Ultimately, both formulations are valid depending on the chosen convention for the tensor operators. Understanding these conventions is crucial for accurate application in quantum mechanics.
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Hi all,

I found a commutation relation of lowering operator(J-) and spherical operator in Shankar's QM (2ed, page 418, Eq 15.3.11):
[J_-,T_k^q] = - \hbar \sqrt{(k+q)(k-q+1)} T_k^{q-1}

I wonder how the minus sign in the beginning of the right hand side come out?

I have googled some pages, some of them have that "-", e.g. :
http://galileo.phys.virginia.edu/classes/752.mf1i.spring03/TensorOperators.htm
the formula appears at the end of this page.

and some has no "-", e.g.:
http://atoms.vuse.vanderbilt.edu/Elements/CompMeth/HF/node30.html
Eq(116) at the beginning .

I also found there's no minus in Messiah's QM (Vol II, page 572, Eq XIII.123a)
[J_-,T_q^{(k)}] = \sqrt{k(k+1)-q(q-1)} T_{q-1}^{(k)}


So, the question is which one is correct?

Thanks :)
 
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Both are correct. It depends on the convention adopted for the T operators. In particular, for a vector operator, it depends on whether T^{\pm 1}_1 = x\pm iy or T^{\pm 1}_1 = \pm(x\pm iy).
 
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Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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