Comparing Impulses in Unequal Mass Collisions

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SUMMARY

In collisions between two unequal masses, the impulse imparted to the smaller mass by the larger mass is equal to the impulse imparted to the larger mass by the smaller mass, as established by the impulse-momentum theorem. This theorem states that impulse is equal to the change in momentum, defined mathematically as impulse ≡ ∫F(t) dt = F_avg Δt = F Δt. The discussion emphasizes that while the contact time and velocities may differ, the forces exerted during the collision remain equal and opposite due to Newton's third law of motion.

PREREQUISITES
  • Understanding of the impulse-momentum theorem
  • Basic knowledge of Newton's laws of motion
  • Familiarity with concepts of force and momentum
  • Ability to interpret equations related to impulse and momentum
NEXT STEPS
  • Study the implications of Newton's third law in collision scenarios
  • Explore the mathematical derivation of the impulse-momentum theorem
  • Investigate how varying velocities affect impulse in collisions
  • Learn about energy conservation in elastic and inelastic collisions
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Physics students, educators, and anyone interested in understanding the dynamics of collisions and the principles of momentum and impulse in mechanics.

Soniteflash
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Homework Statement


In a collision between two unequal masses, how does the impulse imparted to the smaller mass by
the larger mass compare with the impulse imparted to the larger mass by the smaller one?
A) They are equal.
B) It is larger.
C) It is smaller.
D) The answer depends on the ratio of the masses.
E) The answer depends on how fast they are moving.

Homework Equations

/
impulse≡∫F(t)→dt=F⃗ aveΔt=F⃗ Δt[/B]

F⃗ Δt=Δp⃗ =m(v⃗ f−v⃗ i)

The Attempt at a Solution


OK, so there is am Impulse imparted by a bigger mass on a smaller mass and the other way around too.
By definition Impulse is Force x the change in time and with the impulse- momentum theorem it equals the change in Momentum right? So, wouldn't i need the velocity for that then to use the impulse momentum theorem? Wouldn't a smaller mass with less contact time achieve an equal if not higher impulse compared to the impulse of the bigger mass? I am confused. Velocity should affect the time of contact and therefore the impulse right?

 
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Soniteflash said:

Homework Statement


In a collision between two unequal masses, how does the impulse imparted to the smaller mass by
the larger mass compare with the impulse imparted to the larger mass by the smaller one?
A) They are equal.
B) It is larger.
C) It is smaller.
D) The answer depends on the ratio of the masses.
E) The answer depends on how fast they are moving.

Homework Equations

/
impulse≡∫F(t)→dt=F⃗ aveΔt=F⃗ Δt[/B]

F⃗ Δt=Δp⃗ =m(v⃗ f−v⃗ i)

The Attempt at a Solution


OK, so there is am Impulse imparted by a bigger mass on a smaller mass and the other way around too.
By definition Impulse is Force x the change in time and with the impulse- momentum theorem it equals the change in Momentum right?
It is right, the change of momentum is equal to the impulse. Impulse is force X time of interaction between the colliding bodies.

Soniteflash said:
So, wouldn't i need the velocity for that then to use the impulse momentum theorem? Wouldn't a smaller mass with less contact time achieve an equal if not higher impulse compared to the impulse of the bigger mass? I am confused. Velocity should affect the time of contact and therefore the impulse right?
Can be the contact time different for the colliding objects? Is it possible that "A" is in contact with "B" but "B" is not in contact with "A"?
The same about the force. It is a force of interaction between the objects. If "A" exerts force F on "B" what force does "B" exert on "A"?
 

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