Comparing Payment Plans: Calculating Months Needed

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SUMMARY

This discussion focuses on calculating the number of months required for two payment plans for a second-hand van to equalize in total cost. Plan A involves an initial deposit of $4,950, with the first month's payment of $300 and an increase of $20 each subsequent month. Plan B requires a deposit of $7,995, starting with a first month's payment of $61 and decreasing by $10 each month. The equations derived for total payments are P1 = 4950 + (300 + 20(n-1)) for Plan A and P2 = 7995 + (61 - 10(n-1)) for Plan B, which can be solved to find the month 'n' when both plans cost the same.

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nickenrite
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sequences help!

If possible could you show working and eqn^s used thanks.

'moe plans to set up his own painting company so he has been looking for a tidy, recent model, second hand van to transport his equipment to jobs. He sees one that that will be perfect and notes that there are two possible payment regimes.

Plan A: pay a deposit of$4950
first month pay $300
each successive month pay $20 more than the previous month.

PlanB:pay a deposit $7995
first month pay $61each successive month pay $10 less than the previous month.

Calculate how many months it will take before the total paid into planA would be the same amount paid into planB.


thanks for your time:smile:
 
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Plan A: [tex]P_{1} = 4950+(300 + 20(n-1))[/tex]

Plan B: [tex]P_{2} = 7995 + (61-10(n-1))[/tex]

[tex]n = 1[/tex] corresponds to the first month.

Now set [tex]P_{1}=P_{2}[/tex] , and solve for [tex]n[/tex]
 
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