Comparing Sounds: 80 dB, 30 dB, and 50 dB

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SUMMARY

The discussion focuses on calculating the relative loudness of sounds measured in decibels (dB), specifically comparing 80 dB and 30 dB to a reference sound at 50 dB. It is established that a sound at 80 dB is 32 times louder than 50 dB, while a sound at 30 dB is 0.1 times quieter than 50 dB. The logarithmic nature of the decibel scale is highlighted, with the formula R = 10*log(P1/P2) used to derive these relationships. Understanding this logarithmic scale is crucial for accurately interpreting sound levels.

PREREQUISITES
  • Understanding of decibel (dB) scale and its logarithmic properties
  • Basic knowledge of sound power and intensity ratios
  • Familiarity with logarithmic equations and calculations
  • Ability to interpret sound level comparisons
NEXT STEPS
  • Study the logarithmic scale in detail, focusing on its application in sound measurement
  • Learn how to apply the formula R = 10*log(P1/P2) in various sound scenarios
  • Explore the differences between sound pressure level (SPL) and sound power level (SWL)
  • Investigate real-world applications of decibel measurements in acoustics and audio engineering
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Acoustics students, audio engineers, sound technicians, and anyone interested in understanding sound measurement and its implications in various fields.

homevolend
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Homework Statement



How many times quiter or louder is a sound at
1. 80 dB
2. 30 dB
than a sound 50 dB


Homework Equations



dB2=dB1-dB2?

The Attempt at a Solution



Would this just mean

1. 30 dB louder
2. 2 dB softer?

Or how would I finds "times louder".
Sorry for bad english.
 
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homevolend said:

Homework Statement



How many times quiter or louder is a sound at
1. 80 dB
2. 30 dB
than a sound 50 dB


Homework Equations



dB2=dB1-dB2?

The Attempt at a Solution



Would this just mean

1. 30 dB louder
2. 2 dB softer?

Or how would I finds "times louder".
Sorry for bad english.

dB or deciBells are a logarithmic way of expressing ratios:

http://en.wikipedia.org/wiki/Decibel

For sound power (loudness), the equation is R = 10*log(P1/P2)

So if P1 is equal to P2, the ratio R is 0db.

If P1 is equal to 10 * P2, the ratio R is 10dB.

Makes sense?
 

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