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Which is larger? $\sqrt{7}-\sqrt{6}$ or $\sqrt{6}-\sqrt{5}$? Answer without using a calculator.
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The discussion centers on comparing the differences between the square roots of consecutive integers: $\sqrt{7}-\sqrt{6}$ and $\sqrt{6}-\sqrt{5}$. The conclusion, provided by user eddybob123, establishes that $\sqrt{7}-\sqrt{6}$ is greater than $\sqrt{6}-\sqrt{5}$. This is derived from the fact that the function $\sqrt{x}$ is concave, leading to larger differences as the integers increase. The correct solutions were acknowledged from several forum members, including MarkFL and Pranav.
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