Limit of piecewise function using epsilon delta

  • Thread starter Thread starter songoku
  • Start date Start date
Click For Summary
The discussion focuses on proving the limits of a piecewise function as x approaches 2 from the left and right, specifically showing that both limits equal 10. For the left limit, the function is defined as f(x) = x^3 + 2, and for the right limit, it is f(x) = x^2 + 6. Participants discuss how to establish delta (δ) values for each limit without needing a calculator, emphasizing that a common δ can be used for both one-sided limits. The conclusion is that as long as a positive δ exists that satisfies the epsilon-delta definition of limits, the proof is complete. The conversation highlights the importance of focusing on the correct bounds and ensuring clarity in the calculations.
  • #31
songoku said:
By minimum, do you mean ##\delta=\text{min}~(1, \frac{\epsilon}{4})##?
Sorry, my mistake.
I didn't realize that this example is different from the one in post #1. In this example, one function equation works for both sides, so you only get one value for ##\delta## that works for both sides. Taking a minimum is necessary if you get two different answers for ##\delta## for two sides. In that case you should take the minimum of them. Then the minimum would work for both sides.
 
Physics news on Phys.org
  • #32
I am very sorry for late reply

Thank you very much for all the help and explanation pasmith, PeroK, FactChecker, BvU, Gavran, anuttarasammyak
 
  • Like
Likes Gavran, WWGD and PeroK

Similar threads

Replies
2
Views
2K
Replies
16
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K