Limit of piecewise function using epsilon delta

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SUMMARY

The forum discussion centers on proving the limits of a piecewise function as \( x \) approaches 2 from both the left and right. For \( x \to 2^{-} \), the function is defined as \( f(x) = x^3 + 2 \) and for \( x \to 2^{+} \), it is \( f(x) = x^2 + 6 \). The participants discuss the epsilon-delta definition of limits, specifically how to determine the appropriate delta values without using a calculator. The consensus is that a common delta can be established as the minimum of two calculated deltas for each one-sided limit, ensuring the continuity of the function at the point.

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  • Epsilon-delta definition of limits
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  • #31
songoku said:
By minimum, do you mean ##\delta=\text{min}~(1, \frac{\epsilon}{4})##?
Sorry, my mistake.
I didn't realize that this example is different from the one in post #1. In this example, one function equation works for both sides, so you only get one value for ##\delta## that works for both sides. Taking a minimum is necessary if you get two different answers for ##\delta## for two sides. In that case you should take the minimum of them. Then the minimum would work for both sides.
 
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  • #32
I am very sorry for late reply

Thank you very much for all the help and explanation pasmith, PeroK, FactChecker, BvU, Gavran, anuttarasammyak
 
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