Comparison Test: Am I using a good comparison function?

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The discussion centers on determining whether the integral from 1 to 9 of the function -4/(√[3]{x-9}) diverges. A participant suggests using a comparison function, -4/(x-9), to demonstrate that the original function does not diverge by showing that the comparison function converges. However, another contributor points out that a comparison test is unnecessary, as the integral can be evaluated directly as an improper integral by integrating from 1 to a limit M approaching 9. This approach simplifies the analysis and provides a clearer solution to the problem. The conversation highlights the importance of understanding when to apply comparison tests versus direct integration methods.
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Homework Statement


Does the following interval diverge?
\int^9_1 \frac{-4}{\sqrt[3]{x-9}}


Homework Equations





The Attempt at a Solution


Well.. I've used the following function that I think is always less than the above function to prove that the function above DOES NOT diverge (by showing that the function below converges). I'm just wondering if this is an appropriate way of telling that the function above does not diverge...

\int^9_1 \frac{-4}{x-9}
 
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You don't need a comparison test. You can integrate that function. Just treat it as an improper integral. Integrate from 1 to M and let M approach 9.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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