MHB Complete augmented by row operations

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The discussion focuses on transforming a given augmented matrix into reduced row-echelon form using row operations. The initial matrix undergoes operations such as dividing rows and subtracting rows to simplify it. The final result is a matrix that is fully reduced to the identity matrix on the left side, indicating a complete solution. The process demonstrates the effectiveness of row operations in achieving the desired form. Ultimately, the transformation confirms that the original matrix can be reduced to a standard form, showcasing the principles of linear algebra.
karush
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$\left[
\begin{array}{rrrr|r}
1& -5& 4& 0&0\\
0& 1& 0& 1&0\\
0& 0& 3& 0&0\\
0& 0& 0& 2&0
\end{array}\right] $
OK my first move on this is $r_3/3$ and $r_4/2$.
$\left[
\begin{array}{rrrr|r}
1& -5& 4& 0&0\\
0& 1& 0& 1&0\\
0& 0& 1& 0&0\\
0& 0& 0& 1&0
\end{array}\right]$
$r_2-r_4=r_2\quad$
doesn't this whole thing zero out?
 
Last edited:
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yep ... reduced row-echelon form is

$\begin{bmatrix}
1 & 0 & 0 & 0 &0\\
0 & 1 & 0 &0 &0 \\
0 & 0 & 1 & 0 &0 \\
0 & 0 & 0 & 1 & 0
\end{bmatrix}$
 
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