Anonym said:
“one cannot derive that the ground state is unique.” You should write:” I cannot derive that the ground state is unique.”
This is starting to become ridiculous. The statement "one cannot derive that the ground state is unique" is proven in my posts. As such it is not a statement of incompetence, but a statement of impossibility.
(btw, the proof of that statement is by counter example: I set up a simple example which satisfies the proposed axioms for the harmonic oscillator, and which has a degenerate ground state. As such, it is IMPOSSIBLE to find a proof that such an example cannot exist! (which is exactly the claim that "unique ground state" follows from the axioms of the harmonic oscillator))
I did not understand even one single statement and certainly this is not what I have in my mind. But it is not a matter.
It does. If you cannot follow the simple mathematical reasoning I presented in previous posts, then I do not think you are qualified to criticize what I'm qualified to do. Although I am indeed an experimentalist (but not only, I have other degrees too, and I'm preparing others), even an experimentalist knows some mathematics, and the level needed here is what every physicist should know.
To repeat, the starting axioms were those of the "harmonic oscillator", which are:
You have a hilbert space.
1) In that hilbert space, there is a hermitean operator N, which has only whole-number eigenvalues.
2) That operator N = (a+) a, where a+ and a are two operators defined over the space, which are each other's hermitean conjugate and which have the property that:
3a)If | n > is an eigenvector of N with eigenvalue n (integer), then a+ | n > is an eigenvector of N with eigenvalue n+1.
3b)If | n > is an eigenvector of N with eigenvalue n (integer), then a | n > is an eigenvector of N with eigenvalue n - 1 (or is the 0 vector)
(an alternative to the axioms 3a and 3b is to state the commutation relations between N, a and a+)
That's it. These are the axioms one starts with. They are the axioms of the quantum-mechanical harmonic oscillator.
theorem 1:
One can easily prove that n is limited to the positive integers:
Indeed, n = < n | N | n > = (< n | a+) (a | n > ) = | a |n> |^2. So n is the norm of a vector in hilbert space, and must hence be a positive number. It was already an integer (axiom 1), so it must be a positive integer QED.
theorem 2:
All positive integers appear as eigenvalues of N (and not only some).
The proof is again based upon the relation n = ( < n | a+ ) (a | n >), from which it follows that
a |n> = (phase) sqrt(n) |n - 1>
and from which it also follows that
a+ | n > = (phase) sqrt(n+1) |n+1>.
Imagine that the positive integer m doesn't appear in the list of eigenvalues, and that the number k does. Assume k < m for starters. So there exists a vector | k > with eigenvalue k under N. Apply a+, we find a non-zero vector |k+1>. Apply a+ again. We find an eigenvector k+2... Do this m-k times. We find a non-zero vector |k + m - k > with eigenvalue m. So m was, after all, an eigenvalue of N.
Same argument if k > m: we apply a (k - m) times, and we again arrive at a non-zero eigenvector of N with eigenvalue m. So no positive integer m exists which is not an eigenvalue of N. QED.
definition:
we call a *ground state* an eigenvector of N with eigenvalue 0.
theorem 3:
There exists a ground state.
Apply theorem 2 up to eigenvalue 1. There exists hence an eigenvector |1> of N, with eigenvalue 1. Apply a. a | 1 > = 1 |0>, a non-zero vector. Hence there exists a vector |0> with eigenvalue 0 of N. QED.
FALSE theorem 4:
the ground state is necessarily unique.
This cannot be derived from the above axioms. Proof by counter example.
I do not understand what you say and what you want to say. Please provide your formulation of the 5th postulate of the Geometry.
Someone who doesn't know what is the 5th postulate of Euclidean geometry, the 2000 years of looking for a proof of it from the 4 others, and the final realisation that it is an independent axiom, and can hence be altered, which gave rise to the whole class of non-Euclidean geometries, tells me that I have no qualifications to do some maths ?

For your information, the 5th postulate is simply:
"given a line and a point not on the line, there is one and only one line that can be constructed which contains said point, and which is parallel with the given line"
(or equivalent formulations)