Complete Square + Leibniz question (2 questions)

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SUMMARY

This discussion focuses on the mathematical concepts of completing the square and the application of Leibniz notation in calculus. The participants analyze how to derive time from the equations of motion, specifically using the relationships between distance, velocity, and acceleration. They clarify that dividing derivatives in Leibniz notation can simplify to yield time units. Key equations discussed include V = d/t and the manipulation of terms involving gravitational acceleration.

PREREQUISITES
  • Understanding of completing the square in algebra
  • Familiarity with Leibniz notation in calculus
  • Basic knowledge of kinematic equations
  • Concept of derivatives and their physical interpretations
NEXT STEPS
  • Study the process of completing the square in quadratic equations
  • Learn about the application of Leibniz notation in calculus
  • Explore kinematic equations and their derivations
  • Investigate the relationship between derivatives and physical quantities in motion
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Students in mathematics and physics, educators teaching calculus and algebra, and anyone interested in the application of mathematical concepts to physical problems.

Craig Scott
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Homework Statement


1. How did they complete the square for these equations in the picture below? What was their thought process?

2. distance/velocity = time , velocity/acceleration = time , In leibniz notation how does this cancel out?

When you divide, how does it cancel out to give you a time unit?

Homework Equations


1. In picture

2. ds/dt / d2s / dt2

The Attempt at a Solution


1. It seems like it came out of thin air.

2. dt/ds = time?
 

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  • completesq.jpg
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What is 2. in your relevant equations?

##V = d/t \to t = d/V##
You can add A and subtract A (equivalent to adding 0), and it's still the same.
##\frac{v_{y0}x}{v_{x0}} - \frac{gx^2}{2v_{x0}^2} + \frac{v_{y0}^2}{2g} - \frac{v_{y0}^2}{2g} ##
They factored out ## \frac{-g}{2v_{x0}^2} ##

Rearrange it and it might look a little closer.
 
In my relevant solutions it is velocity/acceleration, the way I put it was just in leibniz notation in terms of s(t)
 
I think I was just confused by all the slashes. Sort of makes it look like one big fraction made of fractions.
 
V2y0/2g

How did you find that
 
Craig Scott said:
V2y0/2g

How did you find that
I assume you are asking about getting from the second equation in the image to the third.
Just expand the square in the third equation and simplify. You should arrive at the second equation.
 

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