Complex Analysis Clarification Question

Click For Summary
SUMMARY

The discussion centers on the Maclaurin series for the function 1/(1-z)^3, specifically addressing a potential oversight in a solution that presents the series as 2/(1-z)^3. The participant confirms that to derive the Maclaurin series for 1/(1-z)^3, dividing the equation by 2 is indeed the correct approach. The instructor may have omitted this final step, assuming students would recognize the necessary division. This clarification emphasizes the importance of carefully interpreting problem statements in complex analysis.

PREREQUISITES
  • Understanding of Maclaurin series
  • Familiarity with complex functions
  • Knowledge of differentiation techniques
  • Basic skills in mathematical problem-solving
NEXT STEPS
  • Study the derivation of Maclaurin series for various functions
  • Explore differentiation of power series
  • Review complex analysis textbooks for series expansions
  • Practice solving problems involving series convergence
USEFUL FOR

Students of complex analysis, mathematics educators, and anyone seeking to deepen their understanding of series expansions and differentiation in mathematical contexts.

RJLiberator
Gold Member
Messages
1,094
Reaction score
63

Homework Statement


Problem and solution found here: http://homepages.math.uic.edu/~dcabrera/math417/summer2008/section57_59.pdf

The question I am interested in is #1. In the solution, the instructor differentiates the series to get to:
2/(1-z)^3 = the series.

If I want the Maclaurin series of the function 1/(1-z)^3 then I would have to divide both sides here by 2.
Is this correct or am I missing something hidden? I ask because I believe the question asked for the series 1/(1-z)^3 and not the series of 2/(1-z)^3. So this may have been a mistake on the solutions.

Homework Equations


Not available for this type of question. All information given.

The Attempt at a Solution


PDF
 
Physics news on Phys.org
RJLiberator said:
If I want the Maclaurin series of the function 1/(1-z)^3 then I would have to divide both sides here by 2.
Is this correct or am I missing something hidden?

That is correct.

I ask because I believe the question asked for the series 1/(1-z)^3 and not the series of 2/(1-z)^3. So this may have been a mistake on the solutions.

Unless you can tell us exactly what the question asked for, we have no way to know. It may simply be that the instructor left the last step out since he knew you would realize that it just involved the division by 2.
 
  • Like
Likes   Reactions: RJLiberator
Excellent, thank you for the clarification. I assumed that to be the case, but I've seen some pretty tricky things with series so far and wanted to be sure.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
8
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
7
Views
3K