Complex Analysis: Locus Sketching

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Homework Help Overview

The problem involves sketching the locus defined by the equation |z-2i|=z+3 in the complex plane C. Participants are exploring the geometric implications of this equation.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to interpret the geometric meaning of the locus, questioning whether it could represent a spiral or a part of the real line. There is discussion about the implications of the equation being real and connections to simpler related problems.

Discussion Status

The discussion is active, with participants offering hints and exploring various interpretations of the problem. Some guidance has been provided regarding the nature of the equation, but there is no explicit consensus on the geometric representation yet.

Contextual Notes

Participants are considering the implications of the triangle inequality in their reasoning and are referencing simpler related problems to aid their understanding.

altcmdesc
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Homework Statement



Sketch the locus of |z-2i|=z+3 in C

2. The attempt at a solution

Let z=x+iy, then |z-i|=|x+iy-2i)|=|x+i(y-2)|=(x^2+(y-2)^2)^(1/2)=z+3

The problem is that I can't tell what this means geometrically. Is it a spiral?
 
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altcmdesc said:
Sketch the locus of |z-2i|=z+3 in C

Hi altcmdesc! :smile:

Hint: |z - 2i| is real, so z + 3 must be real, so … ? :wink:
 
So it must be the real line?
 
altcmdesc said:
So it must be the real line?

It must be part of the real line.
 
I'm thinking of this as the simpler problem z=|z-i| first, but I'm having a hard time believing this could be true for any z because of the triangle inequality.
 
altcmdesc said:
I'm thinking of this as the simpler problem z=|z-i| first, but I'm having a hard time believing this could be true for any z because of the triangle inequality.

That's right! :smile:

But how about z+1=|z-i| ? :wink:
 

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