Complex analysis: Sketch the region in the complex plane

Click For Summary

Homework Help Overview

The discussion revolves around sketching regions in the complex plane defined by angular conditions, specifically the set {z: π/4 < Arg z ≤ π} and the circular region {z: |z - 3 + i| < 4}. Participants are exploring the implications of these conditions on the sketching process.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the correct interpretation of angular rotations in the complex plane, particularly the distinction between clockwise and anti-clockwise rotations. There is also confusion regarding the definition of the radius in relation to the angular conditions.

Discussion Status

Some participants have provided clarifications on the angular conditions and the nature of the regions being sketched. There is ongoing exploration of how to accurately represent the regions based on the given conditions, with some expressing uncertainty about the assumptions made regarding the radius.

Contextual Notes

Participants are grappling with the definitions and implications of the angular conditions and the concept of radius in the context of sketching complex regions. There is a noted lack of consensus on certain assumptions, particularly regarding the radius and its relevance to the problem.

Rubik
Messages
95
Reaction score
0

Homework Statement


Sketch:
{z: [itex]\pi[/itex]?4 < Arg z ≤ [itex]\pi[/itex]}

Homework Equations





The Attempt at a Solution


Is it right to assume

z0 = 0 ; a = a (radius = a) ; and taking [itex]\alpha[/itex] = [itex]\pi[/itex]/4 ; [itex]\beta[/itex] = [itex]\pi[/itex]

And now in order to sketch the problem after setting up the complex plane is it correct to to plot z0 at the origin and then from the origin plot [itex]\pi[/itex]/4 by rotating to the right in a clockwise rotation for [itex]\pi[/itex]/4 radians for the first condition and then rotating [itex]\pi[/itex] to the left from the origin (anti-clockwise rotation) for the second condition and then using a solid or dashed line according to the strictly < or ≤ conditions and this gives me the correct region?

Basically I am confused as to how to rotate the angle in terms of clockwise or anti-clockwise according to the conditions given.
 
Physics news on Phys.org
And I am also unsure if my radius is in fact a or am I missing an important step?
 
Hi Rubik! :smile:

do you mean {z: [itex]\pi[/itex]/4 < Arg z ≤ [itex]\pi[/itex]} ?
Rubik said:
… by rotating to the right in a clockwise rotation for [itex]\pi[/itex]/4 radians for the first condition and then rotating [itex]\pi[/itex] to the left from the origin (anti-clockwise rotation) for the second condition …

no, everything is always anti-clockwise

i'm worried why you thought it wasn't :confused:

(and i don't understand where radius comes into it)
 
Oops yep I meant [itex]\pi[/itex]/4.. I was worried asking it haha it has been a long time since I have had to work with complex numbers.. Another thing I have just come across is the region {z : |z - 3 + i| < 4} Does this mean that z0 = (-3,i), and the radius = 4?
 
Rubik said:
{z : |z - 3 + i| < 4} Does this mean that z0 = (-3,i), and the radius = 4?

no, the centre is 3 - i
 
With the first part from your first reply I said radius = a because I am trying to sketch the particular region covered by these angles or is that wrong?
 
Rubik said:
With the first part from your first reply I said radius = a because I am trying to sketch the particular region covered by these angles or is that wrong?

I still don't understand this at all.

What is a, and what has the radius to do with anything? :confused:
 
Well I am not sure I just took it as an assuption.. See if I try and sketch this region I draw both these angles taking them anti-clockwise from the origin, which leaves a region in the 1st and 2nd quadrants and I am just confused as I thought I was suppose to be left with a closed region but is this not the case? I am sorry if this still makes no sense it is hard to explain a drawing in words. :/ So currently I have a line in the direction of [itex]\pi[/itex] going anti-clockwise from (0,0) and then another line in the direction of [itex]\pi[/itex]/4 from (0,0) Is that how the region is suppose to look?
 
Rubik said:
… I have a line in the direction of [itex]\pi[/itex] going anti-clockwise from (0,0) and then another line in the direction of [itex]\pi[/itex]/4 from (0,0) Is that how the region is suppose to look?

Yup. There's no restriction on |z|, so the region goes to infinity.

Goodnight! :zzz:​
 
  • #10
Oh okay thanks so much for all your help and sticking with me through all my confusion! I appreciate it :D
 

Similar threads

Replies
8
Views
3K
  • · Replies 22 ·
Replies
22
Views
2K
Replies
3
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K