Complex arithmetic/Geo Series proof

Click For Summary
SUMMARY

The discussion focuses on proving the equation \(\sum^{N-1}_{n=0} cos(nx) = \frac{sin(N(x/2))}{sin(x/2)} * cos((N-1)x/2)\) using algebraic manipulations. The hint provided refers to the geometric series formula \(\sum^{M}_{n=0} r^{n}= \frac{1-r^{M+1}}{1-r}\). The solution involves recognizing that \(cos(nx)\) can be expressed as the real part of \(exp(inx)\), which allows the sum to be treated as a geometric series. Participants seek guidance on progressing from the hint to a complete proof.

PREREQUISITES
  • Understanding of complex arithmetic and exponential functions
  • Familiarity with trigonometric identities and their manipulations
  • Knowledge of geometric series and their properties
  • Basic proficiency in algebraic manipulation techniques
NEXT STEPS
  • Study the derivation of the geometric series formula in detail
  • Explore the relationship between trigonometric functions and complex exponentials
  • Practice algebraic manipulations involving sums of trigonometric functions
  • Learn about the applications of Fourier series in solving similar problems
USEFUL FOR

Students studying advanced mathematics, particularly those focusing on complex analysis, trigonometry, and algebraic proofs. This discussion is beneficial for anyone looking to deepen their understanding of series and their applications in physics and engineering.

PhysicsMark
Messages
90
Reaction score
0

Homework Statement


Applications from multiple-slit diffraction involve sums like the following. Prove that:

[tex]\sum^{N-1}_{n=0}[/tex] cos (nx) = [tex]\frac{sin(N(x/2))}{sin(x/2)}[/tex] * cos((N-1)x/2)

Homework Equations



According to my instructions, this should involve only algebraic manipulations


Also there is this hint:

Use the geometric series formula:

[tex]\sum^{M}_{n=0}[/tex] r[tex]^{n}[/tex]= [tex]\frac{1-r^{M+1}}{1-r}[/tex]



The Attempt at a Solution


Once again, I apologize for the poor use of Latex. I hope the equation is easily understood. This problem comes from the complex arithmetic section of my book. I originally followed a lot of different trig identity paths until I re-read the part about using only algebraic manipulations.

If possible, I would like a small shove past the hint. I'm not asking for a complete proof here, only a little more light in the right direction. Thanks for taking the time to read.
 
Physics news on Phys.org
cos(nx) is the real part of exp(inx). So the sum of cos(nx) is the real part of the sum of exp(ix)^n. The exponential form is a geometric series.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
1K
Replies
1
Views
1K