Complex Arithmetic - Mathematica agrees with me, textbook says I'm wrong.

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SUMMARY

The discussion centers around the resolution of complex arithmetic involving the expression \((1 - i)^{3/2}\). The user confirms their second solution aligns with Mathematica's output, which supports both their interpretation and the textbook's results. The textbook presents the solutions as \(\sqrt[4]{8}[\cos(\frac{5\pi}{8}) + i\sin(\frac{5\pi}{8})]\) and \(\sqrt[4]{8}[\cos(\frac{13\pi}{8}) + i\sin(\frac{13\pi}{8})]\). The user clarifies that the modulus notation was incorrectly represented in their initial image.

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jdinatale
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Mathematica agrees with my second solution (not the first one though). The back of my textbook says: "\sqrt[4]{8}[\cos(\frac{5\pi}{8}) + i\sin(\frac{5\pi}{8})] and \sqrt[4]{8}[\cos(\frac{13\pi}{8}) + i\sin(\frac{13\pi}{8})]"


Edit: The second z in my picture should be |z|, the modulus.

Edit2: Here are the results from mathematica, confirming that both the textbook AND I are right...

http://www.wolframalpha.com/input/?i=(1+-+i)^(3/2)+=+(8^(1/4))[cos(45pi/8)+++i+sin(45pi/8)]
http://www.wolframalpha.com/input/?i=(1+-+i)^(3/2)+=+[8^(1/4)][cos(+13pi/8)+++isin(13pi/8)]

My question is, how did my textbook get that answer?
 
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You can get rid of multiples of ##2\pi##. For example, you have
$$\frac{21\pi}{8} = \frac{(16+5)\pi}{8} = 2\pi + \frac{5\pi}{8},$$ so your first answer is equivalent to the book's first answer. Similarly, you can show your second answer also matches the book's second answer.
 

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