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I am reading Bruce P. Palka's book: An Introduction to Complex Function Theory ...
I am focused on Chapter III: Analytic Functions, Section 1.2 Differentiation Rules ...
I have yet another question regarding Example 1.5, Section 1.2, Chapter III ...
Example 1.5, Section 1.2, Chapter III, reads as follows:
View attachment 9339
View attachment 9340
About half way through the above example from Palka we read the following:
" ... ... Since $$\mid 1/ \sqrt{z} \mid \ = 1/ \sqrt{ \mid z \mid } \to \infty$$ as $$z \to 0$$ ... ... "
Can someone please explain exactly how/why $$ \ \mid 1/ \sqrt{z} \mid \ = 1/ \sqrt{ \mid z \mid }$$ ... Help will be appreciated ...
Peter
I am focused on Chapter III: Analytic Functions, Section 1.2 Differentiation Rules ...
I have yet another question regarding Example 1.5, Section 1.2, Chapter III ...
Example 1.5, Section 1.2, Chapter III, reads as follows:
View attachment 9339
View attachment 9340
About half way through the above example from Palka we read the following:
" ... ... Since $$\mid 1/ \sqrt{z} \mid \ = 1/ \sqrt{ \mid z \mid } \to \infty$$ as $$z \to 0$$ ... ... "
Can someone please explain exactly how/why $$ \ \mid 1/ \sqrt{z} \mid \ = 1/ \sqrt{ \mid z \mid }$$ ... Help will be appreciated ...
Peter
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