[complex functions] polynomial roots in a convex hull

[rahl___]

Hi everyone,

I've got this problem to solve:

Let W(z) be a polynomial with complex coefficients and complex roots. Show that the roots of W'(z) are in a convex hull of the set of roots of W(z).

My problem is that I don't fully understand the question.

I have found such definition of convex hull:

Given a set of points (z_1, z_2, ..., z_n), we denote convex hull as:
conv(z_1, z_2, ..., z_n) = \{ z = \sum_{k=1}^n \beta_k z_k : \beta_k \in [0,1], \sum_{k=1}^n \beta_k = 1 \}

So I do have to prove, that all the roots of W'(z) [let's denote them as z'_k] must be able to be written in such form:
z'_k = \sum_{k=1}^n \beta_k z_k, where \beta_k are satysfying the conditionsof convex hull and z_k are the roots of W(z).
Am i right?

If so, I thought about this kind of sollution:
we assume that what we have to prove is true, so we can write the roots of W'(z) as:
z'_j = \sum_{k=1}^n \beta_k^{(j)} z_k
Now we write down W'(z) using viete's formulas:
W'(z) = n a_n z^{n-1} - n a_n ( \sum_j \sum_k \beta_k^{(j)} z_k ) z^_{n-2} + n a_n \sum_{i<j} ( \sum_k \beta_k^{(i)} z_k ) ( \sum_k \beta_k^{(j)} z_k ) z^{n-3} - ... + n a_n \prod_j \sum_k \beta_k^{(j)} z_k [dont know why the second part of the equation landed little higher that the first one, sorry for that]
and compare it to the polynomial we get when multyplying W(z) by \sum_k {1} / (z-z_k). What do you think of it? I've tried to do this, but the calculus grow pretty vast and I feel that there is a simplier method of proving this.

I would appreciate if you could tell me wheter I understand the question right and if my idea of solving it looks fine.

thanks for your time,
rahl.

 

[rahl___]

I have found the solution. If no one deletes this thread, I will write how to solve it, maybe it will help someone some day.