(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Force A 250 degrees @ 200 N

Force B 150 degrees @ 300 N

Force C 50 degrees @ 400 N

mass = 40kg

mew = .14

what is acceleration

2. Relevant equations

Fa^2 = Fy net^2 x Fx net^2

Fn = Fg

Ff = Fn x mew

Fnet = Fa - Ff

F= ma

3. The attempt at a solution

Fax=Cos 20 (200) = -187.93

Fay = Sin 20 (200) = -68.40

Fbx = Sin 30 (300) = 150

Fby = Cos 30 (300) = -259.81

Fcx = Cos 50 (400) = 257.11

Fcy = Sin 50 (400) = 306.42

Fx net = 219.18 N

Fynet = -21.79 N

Fa^2 = Fxnet^2 + Fynet^2

Fa^2 = 219.18^2 + -21.79^2

Fa^2 = 48039.87 + -474.80

Fa^2 = 47565.07

Fa = 218.09 N

Fn = 9.81 m/s^2 x 40Kg = 392.40N

Ff = Fn (mew) = 392.40N (.14) = 54.94 N

Fnet = Fa - Ff = 218.09 - 54.94 = 163.15 N

a = F/m = 163.15/40 = 4.08 m/s

I'm just not sure Ive done this correct

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# Homework Help: Three forces on a box in different directions what is the acceleration

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