Complex mapping z ↦ ω = (z − a)/(z − b)

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Homework Help Overview

The discussion revolves around the complex mapping defined by the transformation \( z \mapsto \omega = \frac{z - a}{z - b} \), specifically focusing on its geometric interpretations and properties as a Mobius transformation. Participants explore the implications of this transformation on the unit circle and the behavior of angles associated with points \( a \) and \( b \).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the geometric significance of the transformation, including the relationship between the angles of \( z - a \) and \( z - b \). There is also mention of the uniqueness of Mobius transformations based on the images of three points, prompting questions about established theorems related to these transformations.

Discussion Status

The conversation is active, with participants providing insights into the properties of Mobius transformations and affirming the original poster's reasoning. Some participants express confidence in the original analysis while noting that further established theorems may not be necessary for understanding the current problem.

Contextual Notes

There is an indication that the original poster may be working within specific constraints of a textbook chapter on Mobius transformations, which could influence the depth of discussion and the types of theorems considered relevant.

Hill
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Homework Statement
Consider the complex mapping ##z \mapsto \omega = \frac {z - a} {z - b}##. Show geometrically that if we apply this mapping to the perpendicular bisector of the line-segment joining a and b, then the image is the unit circle. In greater detail, describe the motion of ω round this circle as z travels along the line at constant speed.
Relevant Equations
geometry
All points on that line are equidistant from the points a and b. Thus, the length of ##\frac {z - a} {z - b}## is 1, i.e., the points on the unit circle.
If the angle of ##z - a## is ##\alpha##, and the angle of ##z - b## is ##\beta##, then the angle of ##\frac {z - a} {z - b}## is ##\alpha - \beta##. If the point z is far toward either end of the line, ##\alpha - \beta## is close to zero. If z is in the midpoint between a and b, ##\alpha - \beta = \pi##. Thus, as z travels along the line from one "end" to another, w starts near 1, moves along one half of the unit circle speeding up towards -1, and then slows down again as it continues on the other half of the unit circle toward 1.
Are there other geometric details that I've missed?
 
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This is good, assuming that you have not already studied these transformations before and are supposed to know established theorems for them. They are called "bilinear transformations" or "Mobius transformations". I can not think of anything that you have missed.

PS There is a lot more that can be said about these transformations, but I don't think they will help to prove what you proved.
 
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FactChecker said:
This is good, assuming that you have not already studied these transformations before and are supposed to know established theorems for them. They are called "bilinear transformations" or "Mobius transformations". I can not think of anything that you have missed.

PS There is a lot more that can be said about these transformations, but I don't think they will help to prove what you proved.
Thank you. I see that the next chapter in the textbook is "Möbius Transformations and Inversion."
 
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I personally liked and was impressed by your proof. I think it is the right kind of reasoning to understand analytic functions of a complex variable. Of course, if you have theorems that can be used, that is the first thing to look for. But without applicable theorems, your kind of analysis is good.
 
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