Complex mapping z ↦ ω = (z − a)/(z − b)

Click For Summary
SUMMARY

The discussion centers on the geometric properties of the mapping defined by the function ω = (z − a)/(z − b), where points on this line are equidistant from points a and b, resulting in a unit circle representation. The angles of z - a and z - b, denoted as α and β respectively, determine the angle of the transformation, with specific behaviors noted as z approaches the endpoints or midpoint. The conversation emphasizes the significance of bilinear transformations, also known as Möbius transformations, and their unique characteristics, particularly that a Möbius transformation is uniquely determined by the images of three points. The discussion concludes with an acknowledgment of the importance of established theorems in understanding these transformations.

PREREQUISITES
  • Understanding of complex variables and analytic functions
  • Familiarity with bilinear transformations and Möbius transformations
  • Knowledge of geometric interpretations of complex mappings
  • Basic proficiency in angle calculations in the complex plane
NEXT STEPS
  • Study the properties and applications of Möbius transformations
  • Explore the concept of analytic functions in complex analysis
  • Learn about the geometric interpretations of complex mappings
  • Investigate the significance of point mappings in Möbius transformations
USEFUL FOR

Mathematicians, students of complex analysis, and anyone interested in the geometric properties of transformations in the complex plane will benefit from this discussion.

Hill
Messages
761
Reaction score
597
Homework Statement
Consider the complex mapping ##z \mapsto \omega = \frac {z - a} {z - b}##. Show geometrically that if we apply this mapping to the perpendicular bisector of the line-segment joining a and b, then the image is the unit circle. In greater detail, describe the motion of ω round this circle as z travels along the line at constant speed.
Relevant Equations
geometry
All points on that line are equidistant from the points a and b. Thus, the length of ##\frac {z - a} {z - b}## is 1, i.e., the points on the unit circle.
If the angle of ##z - a## is ##\alpha##, and the angle of ##z - b## is ##\beta##, then the angle of ##\frac {z - a} {z - b}## is ##\alpha - \beta##. If the point z is far toward either end of the line, ##\alpha - \beta## is close to zero. If z is in the midpoint between a and b, ##\alpha - \beta = \pi##. Thus, as z travels along the line from one "end" to another, w starts near 1, moves along one half of the unit circle speeding up towards -1, and then slows down again as it continues on the other half of the unit circle toward 1.
Are there other geometric details that I've missed?
 
  • Like
Likes   Reactions: FactChecker
Physics news on Phys.org
This is good, assuming that you have not already studied these transformations before and are supposed to know established theorems for them. They are called "bilinear transformations" or "Mobius transformations". I can not think of anything that you have missed.

PS There is a lot more that can be said about these transformations, but I don't think they will help to prove what you proved.
 
Last edited:
  • Like
Likes   Reactions: WWGD and Hill
FactChecker said:
This is good, assuming that you have not already studied these transformations before and are supposed to know established theorems for them. They are called "bilinear transformations" or "Mobius transformations". I can not think of anything that you have missed.

PS There is a lot more that can be said about these transformations, but I don't think they will help to prove what you proved.
Thank you. I see that the next chapter in the textbook is "Möbius Transformations and Inversion."
 
  • Like
Likes   Reactions: FactChecker
I personally liked and was impressed by your proof. I think it is the right kind of reasoning to understand analytic functions of a complex variable. Of course, if you have theorems that can be used, that is the first thing to look for. But without applicable theorems, your kind of analysis is good.
 
  • Like
Likes   Reactions: Hill

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 21 ·
Replies
21
Views
4K
Replies
24
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
20
Views
4K
  • · Replies 22 ·
Replies
22
Views
4K
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
14
Views
2K