Complex Number Exponentiation: Finding the Power of z^23 for z = 1+1

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SUMMARY

The discussion centers on the calculation of z^23 for z = 1 + 1, where participants debate the correct answer. The book states the result as 2^16e(i8π), but users argue that the correct expression should be 2^(23/2)e(i(n)θ) based on the polar form of complex numbers. The confusion arises from the interpretation of the exponent and the magnitude of z, leading to a consensus that the book's answer is incorrect.

PREREQUISITES
  • Understanding of complex numbers and their polar representation
  • Familiarity with Euler's formula e^(iθ)
  • Knowledge of exponentiation rules for complex numbers
  • Basic trigonometry, particularly involving π
NEXT STEPS
  • Study the polar form of complex numbers in detail
  • Learn about Euler's formula and its applications in complex exponentiation
  • Explore the properties of complex magnitudes and angles
  • Practice problems involving complex number exponentiation
USEFUL FOR

Students studying complex analysis, mathematicians interested in complex exponentiation, and educators teaching advanced algebra concepts.

Ry122
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Im trouble getting the correct answer for z^23 where z=1+1
The answer in the back of the book says its 2^16e(i8pie)
But z=|z|^(n)e(i(n)theta) Therefore the hypotenuse which is 2^(1/2) when multiplied by 23
should be 2^(23/2) not 2^(16)
 
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You're right, of course. I don't know from where the book got 216.
 
… 32 ≠ 23 …

Ry122 said:
Im trouble getting the correct answer for z^23 where z=1+1
The answer in the back of the book says its 2^16e(i*pie)

Hey guys!

It's obviously z^32 … :rolleyes:

(btw, if you type alt-p, it prints π)
 

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