Complex Numbers identity help

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The discussion focuses on expressing the quotient of two complex numbers, z1 and z2, raised to the third power in the form z = x + yi. Participants highlight the importance of using the exponential form of complex numbers, eiθ = cosθ + i sinθ, to simplify calculations. One user attempts to solve the problem by multiplying by the reciprocal of z2, while another confirms the correctness of the resulting expression. There is a sense of urgency as one participant prepares for an upcoming unit test, indicating a need for clarity and confidence in understanding complex numbers. Overall, the thread emphasizes the application of identities and simplification techniques in complex number calculations.
lunds002
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Homework Statement



Let z1 = a (cos (pi/4) + i sin (pi/4) ) and z2 = b (cos (pi/3) + i sin (pi/3))
Express (z1/z2)^3 in the form z = x + yi.

]2. Homework Equations [/b]



The Attempt at a Solution



a(cos (pi/4) + i sin (pi/4))
b (cos (pi/3) + i sin (pi/3))

I then multiplied the top and bottom by the bottom reciprocal : cos (pi/3) - i sin (pi/3) to get

a(cos (pi/4) x cos (pi/3) + sin (pi/4) sin (pi/3)) + i (sin (pi/4) x cos (pi/3) - sin (pi/3) x cos (pi/4)
 
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Do you know the identity e=cosθ+isinθ?

It will make your calculations easier since you can express it in terms of the exponential function.
 
right, i forget that. thank you
 
I'm not sure if I'm right, I am stuck on this question as well.

I got z=(√2)a3/2b3 - (√2)a3/2b3 i
 
That's right.
 
vela said:
That's right.

That's great. I'm still kind of new to this topic, still not confident with it and I have an unit test coming up in less than a week's time! :eek:
 

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