Complex numbers in the form a+bi

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SUMMARY

The discussion revolves around solving the equation 1/z = (-4 + 4i) and the confusion regarding the correct format of the solution. The user attempted to solve for z by multiplying by the conjugate, resulting in z = -1/8 - i/8. However, the solution was marked incorrect due to formatting issues. It was clarified that complex numbers should be expressed in the standard form z = a + bi, where a and b are real numbers, and suggestions were made to use decimal notation for clarity.

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53Mark53
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Homework Statement



How would I go about solving 1/z=(-4+4i)

The answer that I keep on getting is wrong

The Attempt at a Solution


[/B]
What I did

z=1/(-4+4i)x(-4-4i)/(-4-4i)

z=(-4-4i)/(16+16i-16i-16i^2)

z=(-4-4i)/32

z=-1/8-i/8

This is the answer that I got however it says that it is wrong. I am unsure what else I can do

Thanks for any help
 
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53Mark53 said:

Homework Statement



How would I go about solving 1/z=(-4+4i)

The answer that I keep on getting is wrong

The Attempt at a Solution


[/B]
What I did

z=1/(-4+4i)x(-4-4i)/(-4-4i)

z=(-4-4i)/(16+16i-16i-16i^2)

z=(-4-4i)/32

z=-1/8-i/8

This is the answer that I got however it says that it is wrong. I am unsure what else I can do

Thanks for any help
Your result is right, but you might write it in the form ##-\frac{1}{8}- \frac{1}{8} i##
 
ehild said:
Your result is right, but you might write it in the form ##-\frac{1}{8}- \frac{1}{8} i##
Thanks! I thought I was right, the online quiz that we have must have a mistake then
 
Complex numbers ##z##, have to be expressed in the form ##z= a+bi##, where ##a, b##, are real numbers, this was missing in your solution, the ##"i"##
 
chwala said:
Complex numbers ##z##, have to be expressed in the form ##z= a+bi##, where ##a, b##, are real numbers, this was missing in your solution, the ##"i"##
No, it was there. This is what the OP wrote:
z=-1/8-i/8
 
53Mark53 said:
Thanks! I thought I was right, the online quiz that we have must have a mistake then
Maybe you should write 0.125 instead of 1/8.
 

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