Undergrad Struggling with Moduli in Complex Numbers?

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The discussion centers on a misunderstanding of an example from the Brown-Churchill book regarding moduli in complex numbers. The triangle inequality is applied to clarify the equation, demonstrating that the expression |z^3 + 3z^2 - 2z + 1| can be bounded effectively. A suggestion is made that there may be a typo in the reference to equation (9), indicating it should refer to (10) instead. The participants provide a detailed breakdown of the calculations, confirming the inequality holds true under the given conditions. Overall, the conversation emphasizes the importance of accurately referencing equations and applying mathematical principles correctly.
SamitC
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This may be a simple thing but due to some reason I am not able to understand.
I am not able to understand an example from Brown-Churchill book. I have provided the screenshot in the attached picture. Request help.
 

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I think you may have copied the wrong equation for (9). The triangle inequality says that ##|a+b|\leq|a|+|b|##. Applying that to your equation we get:

$$|z^3+3z^2-2z+1|\leq|z^3+3z^2-2z|+|1|\leq|z^3+3z^2|+|-2z|+|1|\leq|z^3|+|3z^2|+|-2z|+|1|$$
[applying the triangle inequality three times in succession]
$$=|z|^3+3|z|^2+|-2||z|+1$$
[applying (8) ]
$$=|z|^3+3|z|^2+2|z|+1<2^3+3\cdot 2^2+2\cdot 2+1=25$$

EDIT: Just saw Samy's post. I don't have the book but, based on that picture, it looks more likely a typo in that the ref to (9) should be to (10), rather than you miscopying it.
 
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May well be a typo. He is referring to the following:
complex.jpg
 
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andrewkirk said:
I think you may have copied the wrong equation for (9). The triangle inequality says that ##|a+b|\leq|a|+|b|##. Applying that to your equation we get:

$$|z^3+3z^2-2z+1|\leq|z^3+3z^2-2z|+|1|\leq|z^3+3z^2|+|-2z|+|1|\leq|z^3|+|3z^2|+|-2z|+|1|$$
[applying the triangle inequality three times in succession]
$$=|z|^3+3|z|^2+|-2||z|+1$$
[applying (8) ]
$$=|z|^3+3|z|^2+2|z|+1<2^3+3\cdot 2^2+2\cdot 2+1=25$$

EDIT: Just saw Samy's post. I don't have the book but, based on that picture, it looks more likely a typo in that the ref to (9) should be to (10), rather than you miscopying it.
Thank you very much.
 
Samy_A said:
May well be a typo. He is referring to the following:
View attachment 99135
Thank you very much.
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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