Complex Plane Points with Re(z)≤0 and |z|=3

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Homework Help Overview

The discussion revolves around identifying sets of points in the complex plane that satisfy specific conditions related to the real and imaginary parts of complex numbers, as well as their magnitudes. The problem specifically addresses conditions such as Re(z) ≤ 0 and |z| = 3.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the implications of the conditions on the complex plane, questioning how to express the sets of points mathematically. There are discussions about the geometric representation of circles and regions defined by inequalities.

Discussion Status

Participants are actively engaging with the problem, offering interpretations and questioning the clarity of the requirements. Some guidance has been provided regarding the geometric nature of the solutions, but there remains uncertainty about how to present the results and whether the interpretations align with the original problem statement.

Contextual Notes

There are indications of confusion regarding the expectations for presenting solutions, particularly in relation to drawing figures and understanding the implications of the inequalities and equations involved.

  • #31
No it doesnt.
 
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  • #32
Why it doesn't?
 
  • #33
You said these were the conditions :

1. Re(z) \geq 0
2. Im(z) \geq 0
3. |z| \leq 2

Part of your picture is to the left of the vertical axis, so it doesn't satisfy (1). Part of your picture is below the horizontal axis, so it doesn't satisfy (2). And part of it is further away from the origin than 2, so it doesn't satisfy (3).
 
  • #34
Physicsissuef, I see you included points where x < 0 as well as y < 0. Does that not violate two of the requirements?
 
  • #36
Yes, good job!

You might want to indicate the value of the radius in the figure.
 
  • #37
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  • #38
No.

Try getting the equation (or inequality) in terms of x and y first. By now you've seen enough examples that you should be able to do it.

Then draw the figure.
 
  • #39
<br /> <br /> 1 \leq x^2+y^2 \leq 9<br /> <br />
But the question is how will I draw it?
 
  • #40
Do you honestly not recognize equations for simple familiar figures in what you have written? Even after doing numerous similar problems?

To be honest and frank with you, I am wondering how it will be possible for you to answer questions like this on an exam in the future.
 
  • #41
Do you understand that (and why) x^2 + y^2 = r^2 represents a circle with radius r?

Do you understand that x^2 + y^2 &lt; r^2 represents a disk with radius r, not including the boundary?
 
  • #42
Redbelly98 said:
Do you honestly not recognize equations for simple familiar figures in what you have written? Even after doing numerous similar problems?

To be honest and frank with you, I am wondering how it will be possible for you to answer questions like this on an exam in the future.

Redbelly98 please be patient with me... I just started to learn about Complex numbers... I can't be expert with 2 hours of learning for god sake...

Nick89 said:
Do you understand that (and why) x^2 + y^2 = r^2 represents a circle with radius r?

Do you understand that x^2 + y^2 &lt; r^2 represents a disk with radius r, not including the boundary?

For how many times, I understand. r^2=x^2+y^2 because of Pita gore theorem in polar coordinate system.

Lets go back to the problem. Is it like http://i25.tinypic.com/24wya1d.jpg"
 
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  • #43
Is it like that, please I need confirmation. Thank you...
 
  • #44
Yes, that's correct.
 
  • #45
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  • #46
Yes.
 
  • #47
Ok, thanks. And what about this http://i26.tinypic.com/jj360y.jpg"

a)1 \leq |z| \leq 2

b)

<br /> -2 \leq Re(z) \leq 2<br />


<br /> -2 \leq Im(z) \leq 2<br />

c)|z-(1,1)| \leq \sqrt{2}

?
 
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  • #48
(a) and (c) are correct, (b) is wrong.
 
  • #49
-2 \leq Re(z) \leq 2

0 \leq Im(z) \leq 2

It was typo. Now is it correct?
 
  • #50
Yes.
 
  • #51
Ok, thanks. And can you please tell me about this two pictures. http://i31.tinypic.com/18d3py.jpg" I will be very happy if you can confirm me. Thank you once again...
 
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  • #52
Physicsissuef said:
Ok. Thanks. And for |z| \leq 4, is it like http://i31.tinypic.com/511rno.jpg"
Yes, |z|\le 4, in the complex plane, refers to those points, (x,y), whose distance from (0,0) is less than or equal to 4. That consists of the circle with center at (0,0) and radius 4 as well as its interior.
 
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  • #53
Yes, but can you confirm me about the pictures in the above post, they're not same. Thanks.
 
  • #54
Physicsissuef said:
Ok, thanks. And can you please tell me about this two pictures. http://i31.tinypic.com/18d3py.jpg" I will be very happy if you can confirm me. Thank you once again...

Yes they're correct.
 
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  • #55
They are all correct? What about i) 0 &lt; |z| \leq 3? How will I make the disk without zero?
 
  • #56
Usually you put a circle (like an 'o') on the point, instead of a dot.

For example, this could be the line y = 2x + 1, x \neq 3:
Code:
|    /
|   / 
|  o
| /
|/
|_________
 
  • #57
Ok, thank you, and my other tasks are correct? (I mean, with stuff like shadowing and circles like in this case) Is it correct with the angles?
 
  • #58
Yes. Don't worry about these things (how to draw it) too much, as long as it's clear what you mean. If your teacher understands what you mean he will most probably accept it, even if the way you have drawn it is maybe not 100% 'conventional'... (I don't even know if there is any convention for things like this... But it's pretty obvious how you've drawn it, so I think you're going to be ok.)
 
  • #59
Ok. Thank you.
 

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