Complex Polynomial of nth degree

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SUMMARY

The discussion focuses on proving that for a polynomial of degree n, P(z) = a_0 + a_1z + ... + a_nz^n, where n ≥ 1, there exists a positive number R such that |P(z)| > (|a_n||z|^n)/2 for all |z| > R. Participants suggest starting the proof by demonstrating that for sufficiently large |z|, the term |z|^n dominates |a_0|. The approach involves manipulating the polynomial to isolate the leading term a_nz^n and analyzing the behavior of the polynomial as |z| increases.

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Nathew

Homework Statement


Show that if
P(z)=a_0+a_1z+\cdots+a_nz^n
is a polynomial of degree n where n\geq1 then there exists some positive number R such that
|P(z)|>\frac{|a_n||z|^n}{2}
for each value of z such that |z|>R

Homework Equations


Not sure.

The Attempt at a Solution


I've tried dividing through by the nth power of z. That way I can somehow incorporate the R value somehow but I'm not exactly sure where to go from here.

Thanks!
 
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Nathew said:

Homework Statement


Show that if
P(z)=a_0+a_1z+\cdots+a_nz^n
is a polynomial of degree n where n\geq1 then there exists some positive number R such that
|P(z)|>\frac{|a_n||z|^n}{2}
for each value of z such that |z|>R

Homework Equations


Not sure.

The Attempt at a Solution


I've tried dividing through by the nth power of z. That way I can somehow incorporate the R value somehow but I'm not exactly sure where to go from here.

Thanks!

Maybe you could start by showing that for large enough z,

##|z|^n > |a_0|##

And, perhaps, rewrite the equation with everything but ##a_n z^n## on the LHS.

Can you see, without doing any algebra, why it's true?
 
Last edited:

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