Complex Representation of Free Vibration

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SUMMARY

The discussion focuses on the representation of free vibrations using complex numbers, specifically in the context of the equation of motion mx^{..} + kx = 0. The general solution is expressed as x = C1e^{iwnt} + C2e^{-iwnt}, where C1 and C2 can be complex. The confusion arises when transitioning from the complex form to the real representation, as the book suggests using x = C1'cos(wnt) + C2'sin(wnt), which includes both sine and cosine terms. The key takeaway is that it is often more effective to work with complex variables throughout the calculations and only extract the real part at the end.

PREREQUISITES
  • Understanding of differential equations, specifically mx^{..} + kx = 0
  • Familiarity with complex numbers and Euler's formula
  • Knowledge of free vibration analysis in mechanical systems
  • Ability to manipulate trigonometric identities and complex exponentials
NEXT STEPS
  • Study the application of complex numbers in differential equations
  • Learn about the use of Euler's formula in mechanical vibrations
  • Explore the concept of phase in oscillatory systems
  • Investigate the implications of using complex representations in engineering problems
USEFUL FOR

Mechanical engineers, students studying vibrations, and anyone involved in the analysis of oscillatory systems will benefit from this discussion.

koab1mjr
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Hi all

I am struggling with going between various representations of vibrations in paticular the complex form.

I am using Rao as my text btw

so for a free vibration and making it simple no damping the euqation of motion is

mx^{..} + kx = 0

with the general solution being

x = C1e^{iwnt} + C2e^{-iwnt}

Here is where the confusion starts, I am only suposed to consider the real portion of the solution above and disregard the imaginary. So using the euler identity becomes

x = (C1+ C2)cos(wnt) + (C1-C2)isin(wnt)

which is
Now based on the statement above i would disregard the second piece since its imaginary. but the problem is the book follws up with

x = C1'cos(wnt) + C2'sin(wnt) is including the second piece and now considering real. FRom here on I am fine but I am lost on this jump

Any help would be much apreciated.

Thanks
 
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hi koab1mjr! :smile:

(have an omega: ω and try using the X2 and X2 icons just above the Reply box :wink:)

i'm not familiar with the use of complex numbers in this way, but i think the original C1 and C2 are allowed to be complex, so when you take the real parts you do get a combination of cos and sin (alternatively, you get a phase)
 
What you really have is

x = Real part of {(C1+ C2)cos(wnt) + (C1-C2)isin(wnt)}

where C1 and C2 are complex. If you unpick that expression, it amounts to

x = A cos (wnt) + B sin (wnt)

where A and B are real constants. That can be written in a simpler form using complex numbers, namely

x = Real part of {C exp(iwnt)}

where C is a complex constant.

This still represents the complete solution to the differential equation, with two indepedent arbitrary (real) constants, namely the real and imaginary parts of C.

You can then write
x' = Real part of {iwC exp(iwmt)}
etc

However, the "Real part of" is just assumed almost all the time, except in situations where you need to be explicit about exactly what real part you mean. So you would normally just write

x = C exp(iwnt)
x' = iwC exp(iwmt)
etc.

As a general principle, don't try to "discard the imaginary parts" too soon in the math. It is usally simpler to keep all the math in complex variables, and only take the real part at the end to relate the math back to the "real world".
 
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