Complex variables : open connected sets

  • Thread starter Benzoate
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Homework Statement



Let S be the open set consisting of all points such that |z|<1 or |z-2|<1 . State why S is not connected.


Homework Equations





The Attempt at a Solution



According to my complex variables book the definition of a connected set are pairs of points that can be joined by a polygonal line, consisting of a finite number of line segements joined end to end, that lies entirely in S. (Complex variables and applications, Brown).

I guess S is not connected is because both |z| and |z-2| have the same slope and therefore are parallel to each other . Therefore , since both |z| and |z-2| are parallel to each other, line segments are not connected , since parallel lines will not touch each other.
 

Answers and Replies

  • #2
Dick
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Those inequalities don't describe lines. They describe circular discs. |z|<1 is the open unit disc. Want to try rephrasing that explanation?
 
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