Complicated liquid to vapor conversion problem

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    Liquid Vapor
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Discussion Overview

The discussion revolves around the calculation of the volume of vapor produced from a liquid when the pressure inside a closed container is rapidly decreased. Participants explore the implications of pressure changes on phase transitions, specifically focusing on water but also considering other liquids.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant poses a question about calculating the volume of vapor produced from 1 mL of water when the pressure in a 2L container is increased to 100 psi and then rapidly decreased back to 1 atm.
  • Another participant suggests using phase diagrams and the Clausius-Clapeyron equation as potential tools for understanding the phase transition involved.
  • A different participant expresses skepticism about the evaporation occurring simply from depressurization, noting that the volume of vapor is constrained by the container's capacity.
  • One participant questions the method of pressurization and depressurization, indicating that the problem lacks clarity and requires more stringent definitions to avoid assumptions.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the feasibility of the proposed scenario or the methods to calculate the vapor volume. Multiple competing views regarding the conditions necessary for evaporation and the definitions of the problem remain unresolved.

Contextual Notes

Participants highlight limitations in the problem's definition, including the need for equilibrium in thermodynamic processes and the assumptions made about the system's behavior during rapid pressure changes.

JamesBone
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I had a question about the volume of vapor produced from an amount of liquid after increasing the pressure inside a container containing the liquid, then rapidly decreasing it back to the original pressure.

Say you have an amount of water, say 1mL (or another liquid, not sure what descriptors you would need to know, possibly boiling point?) in a closed container, let's say 2L. you pressurize the container (initial pressure 1atm/14.69psi) to a pressure, let's say 100 psi. Now if you immediately decrease the pressure back to 1atm (instantly in less than 1 second), causing the liquid to vaporize, how could you calculate the volume of the now vaporized water in the bottle? in other words, if all of the water in the bottle is not vaporized, how could you calculate the volume that was? If you included other factors such as temperature of the air, water, exact amount of time spent depressurizing the container, physical properties of the liquid, etc. I also know the easiest way to solve this would be to remove the vapor then re-measure the amount of liquid remaining in the bottle, but that shortcut isn't allowed in this problem.

Could someone create a blueprint equation of this problem and solve it using made up amounts? I was trying to figure it out using PV=nRT but I haven't taken chem in a while and couldn't go much further than that. I appreciate any help!
 
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I doubt anyone will sit around and solve your problems for you but we will try and aid you in your search.

You can check out:

1. Phase Diagrams for a pure 1 component-2 phase system.
2. The Clausius-Clayperon Equation can be used.

I'm not sure what you are trying to accomplish by "quickly" lowering the pressure. For Thermodynamics to be applicable you need to system to reach equilibrium.
 
Just depressurizing the container is not a reason for the water to evaporate. And the volume is limited by the container, you are always going to have 2 L of the water vapor.

Something doesn't add up.
 
How are you pressurizing and depressurizing - adding more moles to the container and then removing, using a piston to change the volume, adding and removing heat?

Your problem needs to be defined a bit more streniously, otherwise it is all assumptions.
 

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