1. The problem statement, all variables and given/known data A block that has a weight of 20N, is in equilibrium. It is attached to 3 strings, A, B and C. String A has a tension of 15N to the right of the block. Between String A and B is the angle (a) and between B and C is 90degrees. The tension in String B and C is the same. Calculate the tension and the angle (a). 2. Relevant equations sum of the forces=0 3. The attempt at a solution For the horizontal forces I got: 15+Tcos(a)=Tcos(90+a) And then for the vertical: 20=Tsin(a)+Tsin(90+a) But I don't know how to figure it out from there, or whether they are even right. Any help at all would be greatly apprecaited!