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Use the component method to find the resultant(direction and magnitude) of the three forces shown.

Could someone please verify my answers or tell me where I went wrong.

Ax = 500 Cos 30 = -433N

Ay = 500 Sin 30 = -250N

Bx=-250 N

By= 0

Cx=200 Cos 20 = 187.9N

Cy= 200 Sin 20 = 68.4N

R = (-433-250+187.9)I + (-250 + 0 + 68.4)j

= (-495.1, -181.6)

R = sqrt(-495.1^2 + -181.6^2)

= 527N

Tan Theta = 318.4 / 370.9

Theta = 20.1 deg.

Could someone please verify my answers or tell me where I went wrong.

Ax = 500 Cos 30 = -433N

Ay = 500 Sin 30 = -250N

Bx=-250 N

By= 0

Cx=200 Cos 20 = 187.9N

Cy= 200 Sin 20 = 68.4N

R = (-433-250+187.9)I + (-250 + 0 + 68.4)j

= (-495.1, -181.6)

R = sqrt(-495.1^2 + -181.6^2)

= 527N

Tan Theta = 318.4 / 370.9

Theta = 20.1 deg.