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Use the component method to find the resultant(direction and magnitude) of the three forces shown.
Could someone please verify my answers or tell me where I went wrong.
Ax = 500 Cos 30 = 433N
Ay = 500 Sin 30 = 250N
Bx=250 N
By= 0
Cx=200 Cos 20 = 187.9N
Cy= 200 Sin 20 = 68.4N
R = (433250+187.9)I + (250 + 0 + 68.4)j
= (495.1, 181.6)
R = sqrt(495.1^2 + 181.6^2)
= 527N
Tan Theta = 318.4 / 370.9
Theta = 20.1 deg.
Could someone please verify my answers or tell me where I went wrong.
Ax = 500 Cos 30 = 433N
Ay = 500 Sin 30 = 250N
Bx=250 N
By= 0
Cx=200 Cos 20 = 187.9N
Cy= 200 Sin 20 = 68.4N
R = (433250+187.9)I + (250 + 0 + 68.4)j
= (495.1, 181.6)
R = sqrt(495.1^2 + 181.6^2)
= 527N
Tan Theta = 318.4 / 370.9
Theta = 20.1 deg.
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