Components of a covariant vector

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SUMMARY

The discussion centers on calculating the components of a covariant vector \(\tilde{u}\) defined by \(\tilde{u}(\alpha^i{\vec{e}_i}):= \alpha^3-\alpha^2\) using two basis sets in \(\mathbb{R}^3\). The first basis set is \(\{\vec{e}_1, \vec{e}_2, \vec{e}_3\}\) and the second is \(\{\widehat{\vec{e}_1}, \widehat{\vec{e}_2}, \widehat{\vec{e}_3}\}\). The components of \(\tilde{u}\) relative to the first basis are calculated as \(\tilde{u}(\vec{e}_1) = 0\), \(\tilde{u}(\vec{e}_2) = 1\), and \(\tilde{u}(\vec{e}_3) = 0\). The user expresses confusion regarding the notation and the abstract nature of the problem, seeking simpler explanations and resources for better understanding.

PREREQUISITES
  • Understanding of covariant vectors and dual bases
  • Familiarity with linear algebra concepts in \(\mathbb{R}^3\)
  • Knowledge of vector notation and operations
  • Basic grasp of tensor calculus principles
NEXT STEPS
  • Study the properties of dual bases in linear algebra
  • Learn about covariant and contravariant vectors in tensor analysis
  • Explore resources on linear transformations and their applications
  • Read introductory texts on tensor calculus for clearer explanations
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Students of mathematics and physics, particularly those studying linear algebra and tensor calculus, as well as educators seeking to clarify concepts related to covariant vectors and basis transformations.

roldy
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Homework Statement


Consider the following two basis sets (or triads) in {R}^3:

<br /> \{\vec{e}_1, \vec{e}_2, \vec{e}_3\} := \{(1, 0, 0), (0,1, 0), (0, 0, 1)\}<br />

<br /> \{\widehat{\vec{e}_1}, \widehat{\vec{e}_2}, \widehat{\vec{e}_3}\} := \{(1, 0, 0), (1,1, 0), (1, 1, 1)\}.<br />

Let a covariant vector \tilde{u} be defined by \tilde{u}(\alpha^i{\vec{e}_i} ):= \alpha^3-\alpha^2. Obtain explicitly the components of \tilde{u} relative to the corresponding bases \{\vec{e}_1, \vec{e}_2, \vec{e}_3\} and \{\widehat{\vec{e}_1}, \widehat{\vec{e}_2}, \widehat{\vec{e}_3}\}.


Homework Equations


<br /> \tilde{a}(\vec{b})=\tilde{a}(\beta^j\vec{e}_j):=\alpha_j\beta^j<br />


The Attempt at a Solution


My attempt at a solution is just me running around in a bunch of directions. I really don't have a clear understanding of how to approach this.
 
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Start by computing \tilde{u}(\vec{e}_j) for j = 1,2,3. (These are the components of \tilde{u} relative to the basis \{\vec{e}_1, \vec{e}_2, \vec{e}_3\}, or more properly speaking, relative to the corresponding dual basis.)

Then expand the new basis vectors \widehat{\vec{e}_j} in terms of the \vec{e}_k, and use that to compute \tilde{u}(\widehat{\vec{e}_j}) for j = 1,2,3.
 
I'm actually confused at how to do the first part, calculating \tilde{u}(\vec{e}_j).
I know I need to use this relationship \tilde{u}(\alpha^i{\vec{e}_i} ):= \alpha^3-\alpha^2.

So expanding the relationship:

<br /> \tilde{u}(\alpha^1\vec{e}_1+\alpha^2\vec{e}_2+\alpha^3\vec{e}_3)=\alpha^3-\alpha^2<br />

What does the above actually mean?

I asked my professor about this problem and he helped a little. He actually worked through a portion of it. This is what came about.

<br /> \tilde{u}(\vec{e}_1)=\tilde(u)\left((1)\vec{e}_1+(0)\vec{e}_2+(0)\vec{e}_3\right)=0-0=0<br />

The thing I don't understand about this is why are there basis \vec{e}_1, \vec{e}_2, \vec{e}_3 in the parenthesis when you are trying to figure out \tilde{u}(\vec{e}_1).

I need a really simplified (dumbed down) explanation on this. I'm not used of working with anything so abstract.

Would you know of any books that are easy on the reader?
 
Does anyone else have insight on this problem?
 

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