Composite Functions: Determine gof(x) & foh(x)

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Homework Help Overview

The discussion revolves around determining the composite functions gof(x) and foh(x) using the given functions f(x), g(x), and h(x). The subject area includes composite functions, logarithmic and exponential functions.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants attempt to compute the composite functions by substituting one function into another. Questions arise regarding the correctness of the manipulations, particularly concerning properties of logarithmic and exponential functions.

Discussion Status

Some participants express uncertainty about their calculations and seek validation of their results. There is a focus on clarifying the properties of logarithmic and exponential functions, with specific references to the incorrect application of these properties in the attempts presented.

Contextual Notes

Participants are discussing the implications of mathematical properties on their answers, particularly regarding the additive nature of logarithmic and exponential functions. There is an emphasis on ensuring proper notation and parentheses in their expressions.

DJ-Smiles
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Homework Statement


Determine each of the following composite functions:
a) gof(x)
b)foh(x)

Homework Equations


Where f(x)=e^(3x+2) [e is the exponential function]
g(x)= ln(4x+1)
h(x)= 1/(2x-1)

The Attempt at a Solution


So I have found an answer, I am just unsure if I am correct though. This is what I did:

a) gof(x)=g(f(x))
= ln(4(f(x)+1)
=ln(4e^(3x+2)+1)
= ln4e^(3x+2)+ln1
=(3x+2)*4*lne+ln1
= 4(3x+2)+ln1
=12x+8+ln1
=12x+8

b)foh(x)=f(h(x))
=e^(3(h(x))+2)
=e^(3(1/(2x-1))+2)
=e^(3/(2x-1))+2)Is this the correct working out and answers?
 
Last edited:
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DJ-Smiles said:

The Attempt at a Solution


So I have found an answer, I am just unsure if I am correct though. This is what I did:

a) gof(x)=g(f(x))
= ln(4(f(x)+1)
=ln(4e^(3x+2)+1)
[STRIKE]= ln4e^(3x+2)+ln1[/STRIKE]

b)foh(x)=f(h(x))
=e^(3(h(x))+2)
=e^(3(1/(2x-1))+2)
[STRIKE]=e^(3/(2x-1))+2)[/STRIKE]


Is this the correct working out and answers?

Neither the logarithm nor the exponential are additive functions.

ehild
 
what does that mean and how does it affect my final answers?
 
ln(A+B)≠lnA+lnB. eA+B≠eA+B.
Also check your parentheses.


ehild
 

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