Compound Angles: Find Exact Value of cos(a+b)

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Homework Help Overview

The problem involves finding the exact value of cos(a+b) given that angle a is in the second quadrant with sin a = 2/5 and angle b is in the third quadrant with tan b = 3/4. The context is trigonometric identities and the application of the cosine addition formula.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the cosine addition formula and question the application of the values for sin a and tan b. There is uncertainty about how to derive the exact values needed for the calculation.

Discussion Status

Participants are engaged in clarifying the problem and exploring the necessary values for sin(a) and cos(b). Some guidance has been offered regarding the interpretation of the given values, but there is no explicit consensus on the next steps.

Contextual Notes

There is confusion regarding the interpretation of the trigonometric values provided, with participants emphasizing the need to correctly understand the definitions and relationships in trigonometry without relying on calculators.

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Homework Statement


Angle a is located in the second quadrant where sin a=2/5 and angle b is located in the third quadrant where tan b=3/4. Determine an exact value for cos(a+b) and where it is located.

Homework Equations


cos(a+b)=cosacosb+sinasinb

The Attempt at a Solution


I don't know what I'm doing
 
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xcortz said:

Homework Statement


Angle a is located in the second quadrant where sin a=2/5 and angle b is located in the third quadrant where tan b=3/4. Determine an exact value for cos(a+b) and where it is located.

Homework Equations


cos(a+b)=cosacosb+sinasinb

The Attempt at a Solution


I don't know what I'm doing

Check your formula in (2.) carefully.
 
Ray Vickson said:
Check your formula in (2.) carefully.
cos(a+b)=cosacosb-sinasinb
 
xcortz said:
cos(a+b)=cosacosb-sinasinb

OK, so what is preventing you from applying that?
 
Ray Vickson said:
OK, so what is preventing you from applying that?
They want an exact value, not a decimal answer. I don't know what the exact value is for sin2/5 or tan3/4
 
xcortz said:
They want an exact value, not a decimal answer. I don't know what the exact value is for sin2/5 or tan3/4

Why do you think you need to know those values? Read the question again, carefully.
 
.
 
Ray Vickson said:
Why do you think you need to know those values? Read the question again, carefully.
Because when I plugged the numbers in and solved for an exact value, I got 12.32/5 and it was wrong apparently
 
xcortz said:
Because when I plugged the numbers in and solved for an exact value, I got 12.32/5 and it was wrong apparently

Let me repeat: read the question carefully, and show your work. We cannot tell where you are going wrong if we cannot see the details of what you have done.
 
  • #10
xcortz said:
They want an exact value, not a decimal answer. I don't know what the exact value is for sin2/5 or tan3/4
These value are not correct. It's not sin(2/5) -- it's sin(a) = 2/5, and similar for angle b. You are given that sin(a) = 2/5. Using right triangle trig, you should be able to find the exact value for cos(a) (don't use a calculator), and similarly for sin(b) and cos(b).
 
  • #11
Think about what sine represents in terms of sides of triangle.
 

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