Compressed Springs: 100N Force, 30cm Length, k=1000N/m

  • Thread starter Thread starter brake4country
  • Start date Start date
  • Tags Tags
    Compressed Springs
Click For Summary

Homework Help Overview

The problem involves a spring being compressed against a wall with a specified force and spring constant. The original poster seeks to determine the amount by which the spring is shortened when a force of 100 N is applied.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between the applied force and the spring's reaction force, questioning the calculations and assumptions made regarding the spring's displacement.

Discussion Status

Several participants are exploring different interpretations of the spring constant equation and its application to the problem. There is ongoing clarification regarding the setup of the equation and the meaning of the variables involved.

Contextual Notes

Participants note the importance of using consistent units and question the correct representation of displacement in the equation. There is also confusion about the relationship between the applied force and the spring's response.

brake4country
Messages
216
Reaction score
7

Homework Statement


A man compresses a 30 cm spring against a wall. If he applies a 100 N force and the wall is rigid, by how much does he shorten the spring? (k = 1000 N/m).

Homework Equations


Fs=-kx

The Attempt at a Solution


Drew a FBD and labeled applied force of 100 N and calculated the force of the spring resisting the applied force = 30N. At this point, I do not know where to go with this problem.
 
Physics news on Phys.org
If the force applied is 100N, how can it be that the reaction from the spring is only 30N?
 
Ok. I think I figured this out I just need my work checked please. So the formula is F = -kx. So 100 = 1000(30-x) and x = 30 cm. How does this look?
 
brake4country said:
F = -kx. So 100 = 1000(30-x) and x = 30 cm.
I don't think you mean x=30. Also, be careful with units. Put all distances in metres.
 
Can I use 100 N for the F in F = -kx?
 
brake4country said:
Can I use 100 N for the F in F = -kx?
Yes.
 
If I put everything in meters, I get 40 cm. Here is my calculation:

F = -kx
-100 = -1000(x-0.3)
x = .4 m or x = 40 cm.

Did I set up the math correctly? I am not sure whether it should be x-0.3 or 0.3--x
 
brake4country said:
If I put everything in meters, I get 40 cm. Here is my calculation:

F = -kx
-100 = -1000(x-0.3)
x = .4 m or x = 40 cm.

Did I set up the math correctly? I am not sure whether it should be x-0.3 or 0.3--x
In the equation F = -kx, what does x represent?
 
  • Like
Likes   Reactions: Chestermiller
Ok, my mistake. It should be -100 = -1000(.3x) = 33 cm. If this is correct then I understand.
 
  • #10
brake4country said:
Ok, my mistake. It should be -100 = -1000(.3x) = 33 cm. If this is correct then I understand.
No. Please answer my question regarding what x represents in that equation.
 
  • #11
X is the change (displacement) from its resting position.
 
  • #12
brake4country said:
X is the change (displacement) from its resting position.
Right. You are told F and k. Calculate x.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
Replies
8
Views
6K
Replies
2
Views
5K
Replies
16
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K