Compressibility Factor Pressure For Calculating Fan Power

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SUMMARY

The correct type of pressure used in the compressibility factor, KP, for calculating fan power is debated between static and total pressures. Howden's Fan Engineering book suggests using total pressures, while other sources indicate static pressures. The equations provided for calculating fan shaft power (H) and the compressibility factor (KP) demonstrate that the choice of pressure type may yield negligible differences in results when gas velocities are below a Mach number of 0.3. However, adherence to work standards may necessitate treating the gas as compressible regardless of velocity.

PREREQUISITES
  • Understanding of fan power calculations using the equation H = (Q*PT*KP) / (6356*NT)
  • Familiarity with compressibility factors in fluid dynamics
  • Knowledge of static and total pressure concepts in airflow
  • Basic principles of compressible flow and Mach number
NEXT STEPS
  • Research the implications of using static vs. total pressure in fan power calculations
  • Learn about the effects of compressibility on airflow at varying Mach numbers
  • Explore Howden's Fan Engineering book for detailed methodologies
  • Investigate the application of the compressibility factor in different engineering standards
USEFUL FOR

Mechanical engineers, HVAC professionals, and anyone involved in fan design and performance optimization will benefit from this discussion.

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What is the correct type of pressure (static or total) used in the compressibility factor, KP, when calculating fan power? Howden's Fan Engineering book seems to indicate total pressures should be used, but I also have a PDF from Howden that indicates static pressures should be used. Online searching has shown mixed answers. For my calculation, I did it both ways and the difference was small enough to be considered negligible by engineering judgement, however, I would still like to know the correct calculation.

The equations I am using are:

H = (Q*PT*KP) / (6356*NT)

Where,

H = fan shaft power [hp]
NT = fan total efficiency [%]
Q = fan inlet volumetric flow [acfm]
PT = fan total pressure [in. w.c.]
6356 is a conversion factor
KP = compressibility factor [dimensionless]

KP = \gamma/(\gamma-1) * [(p2/p1)^((\gamma-1)/\gamma)-1] / ((p2/p1)-1)

Where,

p2 = total or static pressure at the fan outlet [in. w.c.]
p1 = total or static pressure at the fan inlet [in. w.c.]
 
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It's going to depend on what velocities are produced by the fan. In flow calculations, a gas can be treated like an incompressible fluid when the flow velocity is below 0.3 M (for air at sea lever, 0.3 M is about 100 m/s).
 
1.) Are you saying that if my gas velocities have a Mach # less than 0.3 I may treat the gas as incompressible with negligible difference in results, and the KP factor does not need to be considered?

2.) Per my work standards I'm required to treat it as compressible. So even if #1 above is correct, I'm still stuck trying to figure out if I should use total or static pressures in the compressibility equation.

3.) A small addendum to the compressibility factor equation shown in blue:

KP = γ/(γ-1) * [(p2/p1)^((γ-1)/γ)-1] / ((p2/p1)-1)

Where,

p2 = total or static absolute pressure at the fan outlet [in. w.c.]
p1 = total or static absolute pressure at the fan inlet [in. w.c.]​
 

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