Compton scattering theory question

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In Compton scattering, when a photon collides with an electron, it transfers energy to the electron, resulting in a decrease in the photon's frequency. Although the photon has no mass, it continues to travel at the speed of light, and its reduced energy is reflected in this frequency change. The collision is considered elastic, meaning total kinetic energy is conserved, along with momentum. Both the photon and electron maintain their energy balance before and after the interaction. This understanding aligns with the principles of conservation of momentum and energy in such collisions.
salmayoussef
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The question is this: When a photon bounces off an electron, it gives some of its energy to the electron. The photon has no mass, however, and it must continue to travel at speed c. How is its reduced energy manifested?

Now, I do somewhat understand what the Compton effect is and I read in my course notes that in an elastic collision (which is what this is, right?) of a photon with an electron, momentum is conserved. Would it make sense to say that the photon transfers energy to the electron and the frequency decreases because of this loss of energy? Could someone please help clarify? Thanks!
 
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Yes, that's exactly what happens.
 
salmayoussef said:
I read in my course notes that in an elastic collision (which is what this is, right?) of a photon with an electron, momentum is conserved.

In any collision, whether elastic or inelastic, momentum is conserved.

A collision is elastic if the total kinetic energy is conserved. This is true for Compton scattering because we have a photon and electron coming in, and a photon and electron going out. The sum of the rest-energies is the same before and after, therefore the total KE is the same before and after.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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