Compute Lim Inf & Lim Sup of Sequence

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SUMMARY

The discussion focuses on computing the limit inferior (lim inf) and limit superior (lim sup) of the sequence defined by the infinite series Σ (1/(2^i) + 1/(3^i)). Participants clarify that the sequence of partial sums, {S_n}, is essential for this computation. The formula for the ratio of consecutive terms, (a_n+1)/(a_n), simplifies to (3n+1 + 2n+1)/(6(3n + 2n)). Additionally, the distinction between even and odd indexed terms is emphasized as crucial for accurately determining the lim inf and lim sup values.

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  • Knowledge of ratio and root tests for convergence
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  • Learn about the ratio test and root test in detail
  • Explore the concepts of limit inferior and limit superior in sequences
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Homework Statement



Given the sequence, 1/2 + 1/3 + 1/(2^(2)) + 1/(3^(2)) + 1/(2^(3)) + 1/(3^(3)) + ..., Describe the terms of the sequence and use it to compute the lim inf (a_n+1)/(a_n); lim sup (a_n+1)/(a_n); lim inf (a_n)^(1/n); lim sup (a_n)^(1/n).

Homework Equations

The Attempt at a Solution



First, I found the formula for the sequence, which is \Sigma i=1 to infinity of [1/(2^(i)) + 1/(3^(i))].

I wrote out some terms of the sequence, but I'm having a hard time pulling out a subsequence to compute the ratio and root tests.
 
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First off, 1/2 + 1/3 + 1/(2^(2)) + 1/(3^(2)) + 1/(2^(3)) + 1/(3^(3)) + ... is an infinite sum (AKA infinite series), not a sequence. Every infinite sum has a sequence associated with it, the sequence of partial sums, {Sn}, which is defined this way:
S_n~=~\sum_{i = 1}^n a_n

Is an defined for your infinite sum? If not, it would be more convenient to define the general term in your series as an = 1/2n + 1/3n. If an is defined in this way or can be defined this way, the ratio an + 1/an is fairly easy to calculate, and comes out to (3n+1 + 2n+1)/(6(3n + 2n)). You should be able to work with this to get your lim sup and lim inf values

On the other hand, if an has a different formula for the even terms and the odd terms, it's going to be more difficult to calculate the aforementioned ratio.
 
The second part of the problem says I should consider both cases, positive and negative, when computing the lim inf and lim sup. I've never seen this type of problem before and I'm totally sure what it is asking me to do.
 
You didn't include that information in your problem description. What do you mean, both cases, positive and negative?
 
Yeah, both cases positive and negative.
 
Again, what do you mean by the positive and negative cases?
 
From my notes: After writing down a formula for {a_n}, describe {a_n} when n is even (n=2k) and when n is odd (2k-1).
 
Last edited:
That information would have answered my questions in post #2. This doesn't have anything to do with positive and negative, but rather, odd and even terms.

So finally, we're getting somewhere.

Here are some more questions.
What do the a2k terms of this series look like?
What do the a2k - 1 terms look like?

If these are too hard, what do a2, a4, a6, and so on look like? Can you generalize this?

What do a1, a3, a5, and so on look like? Can you generalize this?
 
How are you getting the lim inf and lim sup vales out of (3n+1 + 2n+1)/(6(3n + 2n))?
 
  • #10
I'm not. Look at post #8 again, and answer the questions I've asked.
 

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