Compute the mass of the marble?

  • Thread starter Thread starter Max CR
  • Start date Start date
  • Tags Tags
    Marble Mass
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
7 replies · 5K views
Max CR
Messages
121
Reaction score
3

Homework Statement



The gravitational attraction between a 20 kg cannonball and a marble separated center to center by 30 cm is 1.48 x 10^-10 N. Compute the mass of the marble.

Homework Equations





The Attempt at a Solution



Mc = 20 kg
L = 30 cm = 0.3 m.
Fg = 1.48 x 10^-10 N
Mm = ?

Fg = G x mM/r^2
1.48 x 10^-10 N = 9.8 m/s^2 x 20 kg x m/0.3 m^2=
1.48 x 10^-10 N/2177.78 = 2177.78 m/2177.78 =
6.796 x 10^-14 kg
 
Physics news on Phys.org
Fg = G x mM/r^2
1.48 x 10^-10 N = 9.8 m/s^2 x 20 kg x m/0.3 m^2

I almost agree up to there. Two questions: what are you squaring when you write 9.8 m/s^2 and 0.3 m^2? And what is G in that formula?

The rest of your post is just numerics, of which I can only guess what they came from. Can you be more specific as to what you did? For example, first do the calculation with the variables only and plug in the value only later, or at least indicate your steps (now we calculate ... = 2177.78, and plug it into ...)

Just from my intuition, I would say 10^(-14) kg is a bit light for a ball of marble.
 
G in that formula is gravity. Gravity is measured as 9.8 m/s^2. THanks! I know hte answer but I need to know how to get to it.
 
Max CR said:
G in that formula is gravity. Gravity is measured as 9.8 m/s^2.
Not quite. What we measure is [tex]g = G M_\mathrm{earth} / r_\mathrm{earth}^2 \approx 9.81[/tex] m/s^2. G is the gravitational constant which is quite something else (check your textbook).

Max CR said:
THanks! I know hte answer but I need to know how to get to it.
So you don't know the answer :smile:
Once you have found the correct value of G, please try carefully writing down the formula (brackets!), indicating your steps (21777 doesn't mean anything to me) and check your units (m/s^2 * kg^2 / m^2 is not N).
 
Ok I see now. So I ahve this so far and am getting the wrong answer.

Fg = G x mM/r^2

1.48 x 10^-10 N = 6.6726 m/s^2 x 20 kg x m/(0.3m)^2

1.48 x 10^-10 N/1482.8 m. = 1482.8 m./1482.8 m. =

9.98 x 10^-14 kg

This is not correct. What did I do?
 
Ok. I get it now thanks!
 
Good :smile:

Please remember to be careful about your quantities (people don't (just) drag along the units in their calculations because it's so much fun :-p) and to write clearly (for example, between the second and third step write something like: "I calculate 6.6726 m/s^2 x 20 kg /(0.3m)^2 = 1.48 x 10^-10 / 1482.8 N/m, so ...")