How Does a Marble's Speed Change as It Rolls Down a Hemispherical Bowl?

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SUMMARY

The discussion focuses on determining the rotational speed of a marble as it rolls down a hemispherical bowl. The marble, with a radius of 10 mm, is released from a position where it makes a 30° angle with the vertical in a bowl with a radius of 200 mm. Key equations mentioned include angular velocity (w = v/r) and the relationship between linear velocity and period (v = R2π/T). The concept of energy conservation is also raised as a potential method for solving the problem.

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Homework Statement


A marble of inertia m is held against the side of a hemispherical bowl as shown in (Figure 1) and then released. It rolls without slipping. The initial position of the marble is such that an imaginary line drawn from it to the center of curvature of the bowl makes an angle of 30∘ with the vertical. The marble radius is Rm = 10 mm, and the radius of the bowl is Rb = 200 mm .

Determine the rotational speed of the marble about its center of mass when it reaches the bottom.
Mazur1e.ch12.p69.jpg

Homework Equations


w=v/r
v=R2pi/T
maybe idk w=(delta(theta))/(delta(time))

The Attempt at a Solution


i wasn't really sure where to start but i know that change in theta would be pi/6
 
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L Knope said:

Homework Statement


A marble of inertia m is held against the side of a hemispherical bowl as shown in (Figure 1) and then released. It rolls without slipping. The initial position of the marble is such that an imaginary line drawn from it to the center of curvature of the bowl makes an angle of 30∘ with the vertical. The marble radius is Rm = 10 mm, and the radius of the bowl is Rb = 200 mm .

Determine the rotational speed of the marble about its center of mass when it reaches the bottom.
Mazur1e.ch12.p69.jpg

Homework Equations


w=v/r
v=R2pi/T
maybe idk w=(delta(theta))/(delta(time))

The Attempt at a Solution


i wasn't really sure where to start but i know that change in theta would be pi/6

Is energy conserved? If yes, why not use it?
 

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